When is the Resultant Vector Calculated and What is the Formula?

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Homework Help Overview

The discussion revolves around calculating the time of travel given specific distance values and velocity, as well as finding the resultant vector from two components and their angles. The subject area includes kinematics and vector analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the calculation of time using distance and velocity, questioning the original poster's equation. There is also discussion about the method for finding the resultant vector, with some suggesting the use of rectangular coordinates and others referencing Pythagorean theorem.

Discussion Status

The discussion is active, with participants providing alternative interpretations and methods for both the time calculation and resultant vector determination. Some guidance has been offered regarding the need to convert vectors into rectangular coordinates.

Contextual Notes

There is some confusion regarding the initial equation for time and the proper method for calculating the resultant vector, indicating a need for clarification on these concepts. The discussion reflects varying levels of understanding among participants.

daisy7324
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I'm reviewing for my physics exam and I'm kind of stuck on this problem. It gives three values, X1= 10m and X2= 30m and velocity of 35. How much is the time of travel? Can it be as simple as t=(10-20)/35

Another question is give two components and their respective angles, you find the resultant vector by sqroot(component^2+component^2) right? Thanks!
 
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Not sure what your equation means: t=(10-20)/35


Is it a typo? The delta distance is 30m-10m, right?

And on your second question, you should convert the vectors into rectangular coordinates and add them. Then your answer can stay in rectangular coordinates, or you can convert back to polar (magnitude, direction) coordinates.
 
daisy7324 said:
I'm reviewing for my physics exam and I'm kind of stuck on this problem. It gives three values, X1= 10m and X2= 30m and velocity of 35. How much is the time of travel? Can it be as simple as t=(10-20)/35

It is as simple as t = (30-10)/35, if the velocity is in m/s.

Another question is give two components and their respective angles, you find the resultant vector by sqroot(component^2+component^2) right? Thanks!

"sqroot(component^2+component^2)" will not give you the resultant vector, it's just a number equal to the magnitude of the vector.
 
1.constant velocity

v = s/t (m/s)

2. it is Petagorus's rule
when that must be perpendicular components
if not be perpendicular use rhombus calculating
 

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