Where are my mistakes in these derivative problems?

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SUMMARY

This discussion focuses on common mistakes made while differentiating functions, specifically using the product and quotient rules. The user presented four derivative problems, receiving feedback that emphasized the importance of treating constants correctly and applying the chain rule. Key corrections included recognizing square root expressions as power representations and ensuring proper algebraic manipulation. The revised answers provided by the user indicate a better understanding of differentiation principles.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly derivatives
  • Familiarity with the product rule and quotient rule for differentiation
  • Knowledge of power representations for square roots and other functions
  • Ability to perform algebraic manipulations accurately
NEXT STEPS
  • Study the application of the product rule in more complex functions
  • Learn the chain rule in detail, especially for composite functions
  • Practice differentiating functions involving square roots and rational expressions
  • Review common algebraic errors in calculus to improve accuracy
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Students learning calculus, educators teaching differentiation techniques, and anyone seeking to improve their understanding of derivative calculations.

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Hey Everyone,

I cannot believe I am asking questions as stupid as this, but I know I am doing these wrong and want to correct my bad habits. My questions are on derivatives, something I used to be really good at, I'm hoping it will start to come back to me soon. Anyway here they are along with my work:

1) Differentiate square root2 *u + squareroot(3u)

For this one I used the product rule for the first section because you had root 2 multiplied by the constant 2, and for the second I just took the derivative as normal. I ended up getting an answer of:
(squareroot2 + u)/(3/2 square rootu). Sorry if this seems unclear, I don't know how to get the square root sign to show up on the computer.

2) Differentiate (u^-2 + u^-3)(u^5 - 2u^2)

For this I used to product rule of course and these were my steps:

=(u^-2+u^-3)(5u^4-4u) + (u^5-2u^2)(-2u^-3-3u^-4)
=3u^2-2u+2u^-2

I don't know where I went wrong on this one, or if I even did go wrong, but something just doesn't seem right to me.

3) y=(square root x-1)/(square root x+1)


For this one I'm not really sure how to go about showing my work on the computer so I will just write my answer. I used the quotient rule to get it.

y'=(-0.5x-x^-0.5)/(x^0.5+1)^2

Again, I do not know where I'm going wrong or if I did I'm just unsure of my answer.

4) f(x) = (ax+b)/(cx+d)

For this one I treated the a, c and d as constant values. Then I used the quotient rule to differentiate. My biggest problem with this one is that the answer seems to long to be right.
I think it might be a bit easier to show my work on this one:

=((cx+d)(x)-(ax+b)(x))/(cx+d)^2
=((x)(cx-ax+d-b))/(cx+d)^2

Thanks a lot for any help you can give guys, I know I can get this stuff eventually it just takes me awhile to get a good grasp of it sometimes. Sorry for my lack of work shown, I really don't know how to show it on the computer, and I was worried any work I did show would make it even more confusing. Thanks a lot!
 
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Quite a lot of problems here, and I'm afraid I don't have a lot of time with me right now. I'll highlight some things I see.

Question 1:
Square root 2 should be treated as a constant a. Then the derivative of ax would be a due to the power rule. The derivative of terms summed together is their derivatives separately added together.

Question 2:
Your product rule looks fine. I think somewhere there your algebra failed you.

Question 3:
You may be getting confused due to the square roots. Replace the square root by the power representation ^-1/2, so square root (x+1) would be (x+1)^1/2. Keep in mind as well that 1/x = x^-1. You should use the chain rule in full form if you get confused easily.

u = f(x)
du = f'(x)dx
du/dx = f'(x)

dy/dx = du/dx x dy/du

Question 4:
I think you made a blunder when you did d/dx(ax + b ) = x. Wrong! The derivative is a! Redo the quotient rule keeping this in mind.
 
1) Ok, I really don't know what I was thinking for that first question. I changed my method and I got (2u^3/2+square root 3)/(2square rootu)

2) For the second I made an error in expanding out the brackets, my revised answer is 3u^2 + 2u^-2 + 2u

3) For this one I think you misunderstood the question due to my inability to write this out on the computer. I'll try writing it out again:

((square rootx)-1)/((square root x)+1)

4) Once again, I don't know what I was thinking here. My new answer now makes more sense to me, it is (da-bc)/(cx+d)^2

Well, I hope that fixes them, but I'm still unsure of my answers. If anyone could tell me whether I am on the right track or not I would really appreciate their efforts.
 
For 1 you mean (\sqrt{2})u + \sqrt{3u} right?

If so, then you must remember that the first part, square root of 2, is a constant, then for the second part you can do the chain rule.

For 2, you got the same answer I got. For this problem I would have been lazy and expanded the whole thing, and then take the derivative of each part.
 
Last edited:
Yes that is what I mean for question 1. I suppose the new answer I posted in the previous post is still wrong then? If so I don't really know how to go about fixing it.
 
Hmm, I guess I can not understand what your answer is.
I got: \sqrt{2} + \frac{\sqrt{3}}{2\sqrt{u}}
 
Last edited:
Ok, I will try it again and see if I can manage to get what you did, there is more than likely a mistake in mine somewhere. Do my others looks ok now? Thanks again.

*edit* I'm wondering if part of the problem with our answers being different, is that I put everything under a common factor of 2squarerootu. I may still have made an error though, I'm going to have to check that out.
 
Last edited:
*****bump*****
 
Question 1's solution from mattmns is okay and your Question 4. I haven't verified the rest.
 
  • #10
OK, I made a bit of an edit in one of my above posts but I'm not sure if that fixes the issue or not. Thanks again!
 
  • #11
I just realized I made an extremely stupid mistake in the first question so that is now fixed. The others still need a bit of help though.
 

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