Where Did I Go Wrong in Calculating the Proton's Re-emergence Time?

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SUMMARY

The discussion centers on calculating the re-emergence time of a proton in a magnetic field. The proton has a mass of 1.7×10-27 kg and a charge of 1.6×10-19 C, traveling at a speed of 106 m/s in a uniform magnetic field of 1.2 T. The formula used for the radius is r=mv/qB, followed by t=πr/v for time calculation. The correct re-emergence time is 2.8 x 10-8 s, confirming that the initial calculation was off by a power of ten.

PREREQUISITES
  • Understanding of classical mechanics, specifically motion in magnetic fields.
  • Familiarity with the Lorentz force and its application to charged particles.
  • Knowledge of the equations for circular motion and angular displacement.
  • Ability to manipulate scientific notation and powers of ten.
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  • Review the derivation of the Lorentz force and its impact on charged particles.
  • Learn about the principles of circular motion in magnetic fields.
  • Practice calculations involving the radius of curvature for charged particles in magnetic fields.
  • Explore the implications of magnetic fields on particle trajectories in physics simulations.
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This discussion is beneficial for physics students, educators, and anyone interested in the dynamics of charged particles in magnetic fields, particularly in the context of classical mechanics and electromagnetism.

ahazen
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A proton (mass= 1.7×10-27 kg, charge= 1.6×10-19 C) traveling with speed 106 m/s enters a region of space containing a uniform magnetic field of 1.2 T.
What is the time t required for the proton to re-emerge into the field-free region?

I plugged the numbers into r=mv/qB and then t=pi r/ v

I got 2.7815 e-18 but the homework online says I am off by a power of ten.
Anyone know where I went wrong?
Thank you:)
 
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I get 2.8 x 10-8s [to 2 sig figs]
Without seeing your calculation I don't know where you went wrong.
The method is correct. Just check your powers of 10 again.
 


Thank you so much for all your help:) The homework online says your answer is correct:)
 

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