Where did I go wrong (torque/moment problem)

[FaroukYasser]

Homework Statement

In the figure above, what is the torque about the pendulum’s suspension point produced
by the weight of the bob, given that the mass is 40 cm below the suspension point,
measured vertically, and m = 0.50 kg ? (let g = 10 ms^-2 for easier calculations)

Homework Equations

Torque = force x perpendicular distance to the pivot

The Attempt at a Solution

I first got the components of the Weight force:

And I got L using trigonometry:
sin60 = 0.4/L
L = 0.4/sin60
L = (4root3)/15 which is about 0.463

Now torque = F x Perpendicular distance =
5cos60 x L = 5cos60 x 0.463 = 1.15 N.m

But the answer is 2 N.m in the textbook! where have I gone wrong?[/B]

 

[gneill]

I don't think you've gone wrong, I think the textbook has. It looks like they used the wrong angle or the wrong trig function for the calculation of the force component perpendicular to L. Your result looks okay to me.