Where does g force fit in this centripetal motion question?

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SUMMARY

The discussion focuses on calculating the period of a car moving in a vertical circle with a radius of 6 meters and a mass of 800 kg, under the influence of gravity at 9.8 m/s², resulting in a g-force of 6g. The net force equation is established as fnet = ma, leading to the relationship fn + fg = (mv²)/r. The user seeks clarification on how to incorporate g-force into the calculations, particularly at the bottom of the circle, where normal force (fn) and gravitational force (fg) interact. The conversation emphasizes the need to understand radial acceleration in this context.

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  • Understanding of centripetal motion and radial acceleration
  • Familiarity with Newton's laws of motion
  • Knowledge of force equations, specifically net force calculations
  • Basic grasp of g-force and its implications in circular motion
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  • Study the concept of radial acceleration in circular motion
  • Learn how to derive the period of circular motion using the formula T = 2π√(r/g)
  • Explore the relationship between normal force and gravitational force in vertical circular motion
  • Investigate the effects of varying g-forces on objects in circular motion
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Physics students, mechanical engineers, and anyone interested in understanding the dynamics of objects in circular motion, particularly in automotive applications.

Henrybar
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a car goes around a vertical circle; determine the period of one cycle if the radius= 6m mass=800kg, gravity=9.8m/s^2 gforce = 6g

my attempt at the bottom of circle:
fnet=ma
fn+fg=(mv^2)/r
fn+fg=(4∏^2mr)/t^2
t=√4∏^2mr/fn+fg
t=√4∏^2(800)(6)/(fg+fg) <-----value of fn and fg will be in opposite directions

fn≠fg so either fn or fg has to be greater. If they both = mg at the bottom, do i multiply the gforce here? to which one? I originally thought that the g force would be multiplied to fn since there is acceleration towards the centre, but would that even make sense?
 
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Henrybar said:
a car goes around a vertical circle; determine the period of one cycle if the radius= 6m mass=800kg, gravity=9.8m/s^2 gforce = 6g

my attempt at the bottom of circle:
fnet=ma
fn+fg=(mv^2)/r
fn+fg=(4∏^2mr)/t^2
t=√4∏^2mr/fn+fg
t=√4∏^2(800)(6)/(fg+fg) <-----value of fn and fg will be in opposite directions

fn≠fg so either fn or fg has to be greater. If they both = mg at the bottom, do i multiply the gforce here? to which one? why?

Lets break this problem into parts, first what's the radial acceleration?
 

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