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Where does g force fit in this centripetal motion question?

  1. Sep 27, 2015 #1
    • Member warned to use the formatting template
    a car goes around a vertical circle; determine the period of one cycle if the radius= 6m mass=800kg, gravity=9.8m/s^2 gforce = 6g

    my attempt at the bottom of circle:
    fnet=ma
    fn+fg=(mv^2)/r
    fn+fg=(4∏^2mr)/t^2
    t=√4∏^2mr/fn+fg
    t=√4∏^2(800)(6)/(fg+fg) <-----value of fn and fg will be in opposite directions

    fn≠fg so either fn or fg has to be greater. If they both = mg at the bottom, do i multiply the gforce here? to which one? I originally thought that the g force would be multiplied to fn since there is acceleration towards the centre, but would that even make sense?
     
  2. jcsd
  3. Sep 27, 2015 #2

    Student100

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    Education Advisor
    Gold Member

    Lets break this problem into parts, first what's the radial acceleration?
     
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