Where does the plane exist in this parallel axis theorem?

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The discussion centers on the application of the parallel axis theorem, specifically regarding the location of a plane in relation to the given equations for moments of inertia. The area in question is described as an unlabelled rectangular figure that lies within the plane of the page. Participants question whether this area is perpendicular or parallel to the plane, ultimately concluding that it is within the plane itself. The area is defined as the portion enclosed by four lines. This clarification is essential for understanding the application of the theorem in this context.
Benjamin_harsh
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Homework Statement
MOI of an area w.r.t any axis in its plane is equal to the MOI of the
area w.r.t a parallel centroidal axis plus the product of
area and square of the distance between the two axes.
Relevant Equations
##I_{AB} = I_{GXX} + A.(y^{2})##
245272


##I_{AB} = I_{GXX} + A.(y^{2})##

Same applies to CD;
##I_{CD} = I_{GYY} + A.(x^{2})##

In the above statement, "any axis in its plane" where does the plane exist in this sketch?
 
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The area is that unlabelled rectangular figure, and it's in the plane of the page.
 
NascentOxygen said:
The area is that unlabelled rectangular figure, and it's in the plane of the page.
Is that area perpendicular to the plane or parallel to the plane?
 
Benjamin_harsh said:
Is that area perpendicular to the plane or parallel to the plane?
The area is within the plane. It is that portion of the plane enclosed by four lines.
 
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