Where is nuclear binding energy stored?

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SUMMARY

The discussion centers on the concept of nuclear binding energy, specifically addressing the confusion regarding its storage. The mass defect, which is the difference in mass between protons and neutrons and the nucleus, is converted into nuclear binding energy. This energy is released to the environment during the binding process, indicating that a bound system has less energy than its unbound components. Additionally, when unbinding occurs, external energy is supplied and stored as potential energy in the field.

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  • Understanding of mass defect in nuclear physics
  • Familiarity with nuclear binding energy concepts
  • Basic knowledge of potential energy in physics
  • Ability to visualize concepts using gravitational analogies
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  • Research the principles of mass defect in nuclear reactions
  • Study the relationship between nuclear binding energy and stability of nuclei
  • Explore potential energy fields in physics
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Students of nuclear physics, educators explaining binding energy concepts, and anyone interested in the fundamental principles of energy storage in atomic structures.

Arun Muthu
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I understand that the difference in mass between the protons and neutrons and the nucleus itself is called the mass defect, and that this mass defect is converted into nuclear binding energy. What seems to confuse me is where this energy is actually stored. I've been reading 4-5 different textbooks and several sources online but they seem to give conflicting perspectives on the matter. Some say that they are stored within the nucleus itself, whilst others say that they are "released", i.e. transferred to the surroundings. The latter makes more sense to me, as nuclear binding energy is officially defined as the amount of energy required to break apart the protons and neutrons and hence completely disassemble a nucleus.

I'm genuinely confused and would appreciate any help.
 
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Binding energy in an attractive potential is negative, so a bound system has less energy than its unbound components. This means that in the process of binding there is excess energy being released to the environment. Similarly, unbinding requires a supply of external energy.

You could turn the argument around, and using the bound state as the baseline, ask where is the added energy stored when you unbind the components of the nucleus. In which case you could say that the extra energy you supplied is stored in the field (its potential energy).

If nuclear forces are too far removed from your intuitions, try visualising the same thing using gravity. All these concepts apply there accordingly.
 
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Bandersnatch said:
Binding energy in an attractive potential is negative, so a bound system has less energy than its unbound components. This means that in the process of binding there is excess energy being released to the environment. Similarly, unbinding requires a supply of external energy.

You could turn the argument around, and using the bound state as the baseline, ask where is the added energy stored when you unbind the components of the nucleus. In which case you could say that the extra energy you supplied is stored in the field (its potential energy).

If nuclear forces are too far removed from your intuitions, try visualising the same thing using gravity. All these concepts apply there accordingly.
 
Well explained!
 

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