Where is Point B on a Sinusoidal Wave?

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SUMMARY

The discussion addresses the calculation of the coordinates of point B on a sinusoidal wave described by the equation y = (15.0 cm) cos(0.157x - 50.3t). Point A is located at the origin, and point B is defined as the first point along the x-axis where the wave is 60.0° out of phase with point A. The solution determines that the coordinates of point B are (1.05 m, 0.148 m), achieved by converting the phase difference into radians and applying the cosine function.

PREREQUISITES
  • Understanding of sinusoidal wave equations
  • Knowledge of phase difference in wave mechanics
  • Ability to convert degrees to radians
  • Familiarity with trigonometric functions, specifically cosine
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  • Study the properties of sinusoidal waves and their equations
  • Learn about phase shifts in wave mechanics
  • Explore the application of trigonometric functions in physics problems
  • Investigate the implications of wave interference and superposition
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Students studying physics, particularly those focusing on wave mechanics, as well as educators looking for examples of sinusoidal wave calculations.

magisbladius
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Homework Statement



For a sinusoidal wave:

At a certain instant, let point A be at the origin and point B be the first point along the x-axis where the wave is 60.0° out of phase with point A. What is the coordinate of point B?

y = (15.0 cm) cos(0.157x - 50.3t)

Homework Equations

The Attempt at a Solution



x(at point B) = theta + 0 = 60.0° = pi/3 rad = ~1.05 m.
y(at point B) = (0.150 m) cos(0.157[1.047 m] - 50.3[0]) = 0.148 m

(x, y) = (1.05, 0.148) m

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I don't understand what the question is asking for. I am handing this in, online, and it checks the answers (I have 3 tries left).
 
Last edited:
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I found the answer.
 

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