Where is Point B on a Sinusoidal Wave?

AI Thread Summary
The discussion revolves around determining the coordinates of point B on a sinusoidal wave, specifically where it is 60.0° out of phase with point A at the origin. The wave is described by the equation y = (15.0 cm) cos(0.157x - 50.3t). The calculation shows that the x-coordinate for point B is approximately 1.05 m, and the corresponding y-coordinate is about 0.148 m. The final coordinates for point B are (1.05, 0.148) m. The user expresses initial confusion about the question but ultimately finds the correct answer.
magisbladius
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Homework Statement



For a sinusoidal wave:

At a certain instant, let point A be at the origin and point B be the first point along the x-axis where the wave is 60.0° out of phase with point A. What is the coordinate of point B?

y = (15.0 cm) cos(0.157x - 50.3t)

Homework Equations

The Attempt at a Solution



x(at point B) = theta + 0 = 60.0° = pi/3 rad = ~1.05 m.
y(at point B) = (0.150 m) cos(0.157[1.047 m] - 50.3[0]) = 0.148 m

(x, y) = (1.05, 0.148) m

-------------------------------

I don't understand what the question is asking for. I am handing this in, online, and it checks the answers (I have 3 tries left).
 
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I found the answer.
 

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