Where is this piecewise function discontinuous?

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SUMMARY

The piecewise function g(x) is defined as g(x) = 3 for x < -4, g(x) = 7+x for |x| ≤ 4, and g(x) = x^4 for x > 4. There is a jump discontinuity at x=4, where g(4) equals 11, while the left-hand limit approaches 256 as x approaches 4 from the left. In interval notation, the discontinuity can be expressed as (4, 11) indicating the gap between the limit and the function value at that point.

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Ianfinity
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g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4



I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
 
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Ianfinity said:
g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4


I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
Hello Ianfinity. Welcome to PF !

Yes, g(x) is discontinuous at x=4.

The limit of g(x) is 256 as x → 4-,

not: the limit of x is 256 as x → 4-.
 

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