Where is this piecewise function discontinuous?

  • Thread starter Ianfinity
  • Start date
  • #1
5
0
g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4



I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
 

Answers and Replies

  • #2
SammyS
Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,324
1,008
g(x) = 3 if x < -4
g(x) = 7+x if |x| <or= 4
g(x) = x^4 if x > 4


I know there is a jump discontinuity at x=4. How would I state that in interval notation? Is that even possible or is it good enough to say g(x) is discontinuous at x=4? Basically what I've found is that if x=4 then g(x)=11 and that the limit of x is 256 as x approaches 4 from the right.

This is part of my review for the test I will be having today. Thanks in advance for the help.
Hello Ianfinity. Welcome to PF !

Yes, g(x) is discontinuous at x=4.

The limit of g(x) is 256 as x → 4-,

not: the limit of x is 256 as x → 4-.
 

Related Threads on Where is this piecewise function discontinuous?

Replies
7
Views
847
Replies
4
Views
1K
Replies
2
Views
532
Replies
2
Views
1K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
11
Views
494
  • Last Post
Replies
9
Views
7K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
7
Views
3K
Top