Where to Place an Object Between Two Light Sources for Least Illumination?

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SUMMARY

The discussion focuses on optimizing the placement of an object between two light sources to minimize illumination. Given two light sources, one three times stronger than the other and positioned 10 feet apart, the total illumination (IT) received by the object is the sum of the illuminations from both sources. The relationship is defined by the equation IT = I1 + I2, where I = ks/d². To find the optimal position, participants suggest differentiating the total illumination expression with respect to distance.

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  • Understanding of inverse square law in illumination
  • Familiarity with calculus, specifically differentiation
  • Knowledge of optimization techniques
  • Basic principles of light intensity and strength
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Students in physics or mathematics, educators teaching optimization techniques, and anyone interested in the practical applications of calculus in real-world scenarios involving light and illumination.

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Homework Statement


The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportional to the square of the distance from the source. If two light sources, one three times as strong as the other, are placed 10 feet apart, where should an object be placed on the line between the sources so as to receive the least illumination?


Homework Equations


1/illumination=distance^2 and illumination=strength. 1/3x=y distance=10 so 1/100= illumination??


The Attempt at a Solution


find the derivative of what equation to optimize?
 
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Let s = strength of a source
Let d = distance from source.

I =ks/d2

The way I read this is that the total illumination an object receives is the sum of the illuminations from the two light sources, so
IT = I1 + I2

From this relationship you should be able to write the total illumination an object at a distance of x feet from the left source gets.

Then differentiate the expression for IT.
 

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