Which Fairies are Telling the Truth?

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    2015
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SUMMARY

This discussion revolves around a logic puzzle involving three fairies: A, B, and C, with specific truth-telling behaviors based on their colors. Merlin explains that pink fairies always tell the truth while green fairies always lie, and transformations between the two can occur without altering their inherent truthfulness. The statements made by the fairies lead to a logical deduction process to classify each fairy and determine A's true nature. The solution is attributed to "Merlin Book of Logic Puzzles" by Margaret C. Edmiston.

PREREQUISITES
  • Understanding of logical reasoning and deduction.
  • Familiarity with truth-tellers and liars in logic puzzles.
  • Basic knowledge of conditional statements in logic.
  • Awareness of the concept of disguises in logical scenarios.
NEXT STEPS
  • Study logical deduction techniques in puzzles.
  • Explore conditional logic and its applications in problem-solving.
  • Investigate other logic puzzles involving truth-tellers and liars.
  • Read "Merlin Book of Logic Puzzles" by Margaret C. Edmiston for more examples.
USEFUL FOR

This discussion is beneficial for puzzle enthusiasts, logic students, and educators looking to enhance their understanding of logical reasoning and problem-solving strategies.

Ackbach
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Here is this week's POTW:

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Merlin and Arthur are magically transported to a land of pink and green fairies. Merlin explained to Arthur, "Real pink fairies always tell the truth, and real green fairies always lie. However, it is within my power to change a pink fairy to a green fairy, or a green fairy to a pink fairy, or both. A pink fairy disguised as a green fairy still always tells the truth, while a green fairy disguised as a pink fairy still always lies. Now, here are three fairies. Each will make a statement. Provide a classification of each fairy and answer the question, 'Does A appear to be a green fairy or a pink fairy?'"

A: B is a pink fairy.
B: If A is a pink fairy, then C is a green fairy.
C: B is a green fairy or A is what she appears to be.

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No one answered this week's question, which I must now attribute to the book Merlin Book of Logic Puzzles, by Margaret C. Edmiston. Here is her solution:

A and B are pink; C is green; A appears to be green. We show that A and B must be the same kind of fairy (in essence, that is, not necessarily in appearance). Suppose they are two different types. First, suppose A is pink and B is green. This cannot be the case, because if A were a pink fairy, she would not make the false statement that B is pink. Now, suppose A is green and B is pink. This cannot be the case either, because if A were a green fairy, she would not make the true statement that B is pink. So A and B are either both pink fairies of both green fairies. Suppose they are both green. Then A is green, so the "if" part of B's statement ("A is a pink fairy") is false. This means that B's statement is true, a contradiction of the assumption that B is a green fairy. So both A and B are pink fairies. Therefore since A is a pink fairy and B has made a true "if-then" statement, it follows that C is a green fairy.

Then, remembering what it means for an "or" statement to be false, we know that both parts of C's statement are false (since C is green). Hence, "A is what she appears to be" is a false statement. So A must appear to be green.
 

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