Which of the dicontinuities are removable?

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SUMMARY

The discussion centers on the continuity of the function f(x) = 1/(x^2 + 1). Participants conclude that there are no discontinuities in this function, as the denominator x^2 + 1 is never zero for any real value of x. Therefore, the function is continuous everywhere on its domain. The confusion arises from the misunderstanding of the function's behavior at potential discontinuities.

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Homework Statement

Find the x values if any for which x is not continuous.Which of the dicontinuities are removable?

Homework Equations

f(x)=1/(x^2+1)

The Attempt at a Solution

Its unfactorable at the bottom ,i tried to factor it.Would this mean there are no discontinuities?
 
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Are you sure you wrote down the problem correctly. It is undefined when the denominator is zero but x^2 + 1 is never zero. Or maybe the answer is that it is continuous everywhere.
 
thanks
 

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