Which of the following must be true about the area A of the triangle?

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SUMMARY

The area A of a triangle is determined by the formula A = (1/2) * b * h, where b is the base and h is the height. In this discussion, it is established that if the base b is increasing at a rate of 3 inches per minute and the height h is decreasing at the same rate, the area A will only decrease when the base b is greater than the height h. This conclusion is supported by the analysis of the rates of change and the relationship between the dimensions of the triangle.

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  • Understanding of triangle area formula: A = (1/2) * base * height
  • Knowledge of calculus concepts, specifically derivatives and rates of change
  • Familiarity with partial derivatives and their application in multivariable functions
  • Basic algebra skills for manipulating equations and inequalities
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  • Learn how to apply the chain rule in the context of related rates
  • Explore examples of area changes in geometric shapes under varying conditions
  • Investigate the implications of increasing and decreasing functions in calculus
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Students studying calculus, particularly those focusing on related rates and geometric applications, as well as educators looking to explain the dynamics of triangle area changes under varying conditions.

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Homework Statement



If the base b of a triangle is increasing at a rate of 3 inches per minute while its height h is decreasing at a rate of 3 inches per minute, which of the following must be true about the area A of the triangle?

a. A is always increasing
b. A is always decreasing
c. A is decreasing only when b < h
d. A is decreasing only when b > h
e. A remains constant

Correct answer is d. A is decreasing only when b > h

Homework Equations





The Attempt at a Solution



I don't understand why the answer is d. If the area of a triangle is (1/2)(base)(height) and the base increases by 3 while the height decreases by 3, wouldn't they just cancel out each other?

Moreover, I don't understand why the area would only be decreasing when the base is bigger than the height and not vice versa. But I guess I won't understand this part until I understand why the area can't be constant.
 
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lude1 said:

Homework Statement



If the base b of a triangle is increasing at a rate of 3 inches per minute while its height h is decreasing at a rate of 3 inches per minute, which of the following must be true about the area A of the triangle?

a. A is always increasing
b. A is always decreasing
c. A is decreasing only when b < h
d. A is decreasing only when b > h
e. A remains constant

Correct answer is d. A is decreasing only when b > h

Homework Equations





The Attempt at a Solution



I don't understand why the answer is d. If the area of a triangle is (1/2)(base)(height) and the base increases by 3 while the height decreases by 3, wouldn't they just cancel out each other?

Moreover, I don't understand why the area would only be decreasing when the base is bigger than the height and not vice versa. But I guess I won't understand this part until I understand why the area can't be constant.

You need to find the dA/dt. Since A is a function of both h and b, and both can be assumed to be functions of t, dA/dt will involve the partial derivatives with respect to h and the partial derivative with respect to b.
 
To see why the area wouldn't be constant, take a triangle with height a and base b. Then its area would be ab/2, right? Now suppose that a minute passes. So now it has base b+3 and height a-3.

Find the area of the new triangle and figure out when it's larger or smaller than the other one.
 

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