Which pulley system requires the least force to lift the same weight?

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SUMMARY

The discussion centers on determining which pulley system requires the least force to lift a weight, with a focus on the mechanical advantage (MA) of various systems. The E system is identified as the most efficient, boasting a mechanical advantage of 3, while systems A, B, C, and D have mechanical advantages of 1, 2, 2, and 2 respectively. The key insight is that the number of strings supporting the weight in system E allows for a reduction in the tension required, effectively reducing the force needed to lift the weight to one-third of its total weight.

PREREQUISITES
  • Understanding of mechanical advantage in pulley systems
  • Basic knowledge of force equations, specifically F = m * a
  • Familiarity with the concept of tension in strings
  • Ability to analyze simple mechanical systems
NEXT STEPS
  • Research the principles of mechanical advantage in different pulley configurations
  • Explore the implications of tension in multi-string pulley systems
  • Study the physics of force distribution in static systems
  • Learn about the applications of pulley systems in engineering and construction
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Students studying physics, engineers designing mechanical systems, and anyone interested in optimizing lifting mechanisms using pulley systems.

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Homework Statement



http://data.imagup.com/10/1146555432.jpg

Homework Equations



Force applied on the weight=F*(MA).

The Attempt at a Solution


i chosse the E system ...it has the greater mechanical advantage (MA)=3.
MA(of A)=1, MA(of B)=2,MA(C)=2,MA(D)=2,MA(E)=3..
I hope my suggestions are correct ! :)
 
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I agree with you. The 'trick' in these question is to ignore the pulley connected to the ceiling, this pulley simply changes the direction of the rope.
Count the number of strings holding up the weight, in E it is 3... Therefore this needs the smallest tension in the string (1/3 the weight)
 
What do you think F = m a hass to do with this problem?
 

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