Why are Fe, Ni, Co ferromagnetic among metals?

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    Ferromagnetic Metals
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SUMMARY

Iron (Fe), cobalt (Co), and nickel (Ni) exhibit ferromagnetism due to their unique electronic structures, particularly the behavior of their D-band electrons. Unlike other metals, these transition metals have unpaired electrons that contribute to their magnetic properties, influenced by the Stoner model of ferromagnetism. The correlation between magnetic properties and the number of electrons is complex, as it involves the density of states in the D-band rather than a simple odd/even classification. The discussion highlights the limitations of existing resources, such as Wikipedia, in providing comprehensive explanations.

PREREQUISITES
  • Understanding of ferromagnetism and the Stoner model
  • Knowledge of electronic configurations in transition metals
  • Familiarity with D-band electron behavior
  • Basic principles of magnetism, including paramagnetism and diamagnetism
NEXT STEPS
  • Research the Stoner model of ferromagnetism in detail
  • Explore the relationship between electron configurations and magnetic properties in transition metals
  • Investigate the density of states in D-band electrons
  • Examine the magnetic properties of other transition metals beyond Fe, Co, and Ni
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Physicists, materials scientists, and students studying magnetism, particularly those interested in the magnetic properties of transition metals and their applications in technology.

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What makes Fe, Co and Ni ferromagnetic compared to all other metals (with exception of Gd, Dy and some exotic alloys according to Wikipedia)? If other ferromagnetic metals just have lower Curie temperatures then why is it so?

Sub-question:
In pure metals is there any correlation in magnetic properties (paramagnetic/diamagnetic) vs number of electrons (odd/even) - analogously to N2 molecule with all electrons paired being diamagnetic, while O2 has unparied electrons and is paramagnetic.
 
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It has to do with the density of states of the D band. The energy spacing between states is small enough that the cost of energy of moving some antiparallel electrons up to higher energy parallel states (because the lower energy states are already occupied) is met by the energy gained from interaction with the magnetic field. I can't answer your sub-question.
 
The Wiki entry is a bit... suboptimally helpful, but I'm sure you can find better explanations of the Stoner model of ferromagnetism.

http://en.wikipedia.org/wiki/Stoner_criterion

To the sub-question:

Yes, this is somewhat related. However, since in these transition metals the magnetically active electrons reside in the D-shell, the dependence on the number of electrons is a bit more complicated than just odd/even. Again, the Wiki page leaves room for improvement, but also provides some hints and keywords to follow up upon.

http://en.wikipedia.org/wiki/Spin_states_(d_electrons)
 

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