Why are Pauli Matrices Invariant under Rotation?

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Pauli Matrices remain invariant under rotation due to their mathematical structure as matrices that represent spin operators. The rotation operator can be expressed using the exponential of a Pauli matrix, incorporating an arbitrary unit vector and the angle of rotation. It is essential to rotate both the spinor indices and the vector index to maintain this invariance. The relationship can be described by the equation sigma_i = R_ij (U sigma_j U^dagger), where U is the rotation operator. This demonstrates that the invariance is a result of the combined transformations of both indices during rotation.
shehry1
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Homework Statement


Can anyone tell me why Pauli Matrices remain invariant under a rotation.


Homework Equations


Probably the rotation operator in the form of the exponential of a pauli matrix having an arbitrary unit vector as its input. It may also be written as:
I*Cos(x/2) - i* (pauli matrix).(unit vector) * Sin(x/2) where x is the angle of rotation.

See Sakurai 3.2.44


The Attempt at a Solution

 
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shehry1 said:

Homework Statement


Can anyone tell me why Pauli Matrices remain invariant under a rotation.


Homework Equations


Probably the rotation operator in the form of the exponential of a pauli matrix having an arbitrary unit vector as its input. It may also be written as:
I*Cos(x/2) - i* (pauli matrix).(unit vector) * Sin(x/2) where x is the angle of rotation.

See Sakurai 3.2.44


The Attempt at a Solution


Pauli Matrices are just matrices... they are just arrays of numbers. They don't rotate.
 
It's because you need to rotate both the spinor indices AND the vector index; let
U = I*Cos(x/2) - i* (pauli matrix).(unit vector) * Sin(x/2) where x is the angle of rotation, and let R_ij be the corresponding matrix that would rotate a vector by the angle x about the unit vector. Then

sigma_i = R_ij (U sigma_j U^dagger)

where j is summed and the spinor indices are suppressed.
 

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