Why are there two values of Hy here?

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SUMMARY

The discussion centers on the calculation of the vertical reaction force Hy in a static equilibrium problem involving moments and forces. Two different equations yield conflicting values for Hy: 16.3043 from the moment about point H and 66.3043 from the moment about point I. The inconsistency arises from the assumptions made regarding the sign of the forces and the distances used in the calculations. Additionally, the question of whether member DI is a two-force member is raised, indicating a need for clarity on the structural analysis principles involved.

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Homework Statement



66wumq.jpg


Homework Equations



∑M at H = 0 and ∑M at I = 0
∑Fy = 0

The Attempt at a Solution


Assuming that Iy is positive and Ix is negative; Hy is negative and Hx is positive.

Now I would like to compute for Iy and Hy using
∑M at H = 0 = Iy(2.3) - 50(3.05)
Iy = 66.3043
∑Fy = 0 = -50 + 66.3043 - Hy = 0
Hy = 16.3043

But if I use
∑M at I = 0 = Hy(2.3) - 50(3.05)
Hy = 66.3043

Why do I have different values for Hy?Also, is DI a two force member?
 
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But if I use
∑M at I = 0 = Hy(2.3) - 50(3.05)
Are you sure about that 3.05 distance?
 

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