Why can't a closed conductor have excess charge inside?

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SUMMARY

A closed conductor in a static situation cannot have excess charge inside it; any excess charge resides on the surface. This behavior is explained by Gauss's Law, which states that the electric field inside a conductor must be zero to prevent net current and charge redistribution. Consequently, for any closed surface within the conductor, the integral of the electric field is zero, indicating no net charge is enclosed. Therefore, the charge density within the conductor must be zero at all points.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Knowledge of electric fields and charge distribution
  • Familiarity with the properties of conductors in electrostatic equilibrium
  • Basic concepts of static electricity and charge behavior
NEXT STEPS
  • Study Gauss's Law applications in electrostatics
  • Explore the behavior of electric fields in different conductor shapes
  • Investigate charge distribution on conductors in static equilibrium
  • Learn about the implications of electric fields in non-static situations
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Students of physics, electrical engineers, and anyone interested in understanding electrostatics and the behavior of conductors in electric fields.

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the interior of a closed conductor can have no excess charges in the static situation ...and even if they have excess charge ...then these charge resides on the surface of the conductor...not inside it...

can anyone explain to me...y a closed conductor behaves so?

wht connection does it have with gauss law for electrostatics?

the conductor can be either..a hollow or solid cylinder or ...even a solid wire..
 
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If there was an electric field inside the conductor, then there would be a net current and hence redistribution of charge. This tells us that there can be no electric field inside the conductor in the static situation. Gauss law relates the integral of the field over a surface to the charge enclosed by the surface. If we pick any surface within the conductor, the integral is going to be zero since the field is. Thus, there can be no net charge enclosed by the surface. Since this is true for any closed surface in the conductor, the charge density must be zero everywhere.
 

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