Why Do Absorbance Values Change in the Difference Spectrum of 4-Nitrophenol?

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SUMMARY

The discussion centers on the difference spectrum of 4-nitrophenol, specifically analyzing the absorbance values derived from the Beer-Lambert law. The difference spectrum reveals that absorbance values can be greater than 0, less than 0, or equal to 0 at specific wavelengths due to variations in molar absorptivity (a) and concentration (c) across the spectrum. The isosbestic point, where the basic and acidic graphs intersect, indicates equal molar absorptivity for both species, explaining the zero absorbance value at that wavelength. Understanding these principles is crucial for interpreting spectral data in chemical analysis.

PREREQUISITES
  • Understanding of the Beer-Lambert law (A = abc)
  • Familiarity with absorbance and transmittance concepts
  • Knowledge of isosbestic points in spectroscopy
  • Basic principles of spectral analysis and graph interpretation
NEXT STEPS
  • Investigate the impact of molar absorptivity on absorbance values in different solvents
  • Learn about the significance of isosbestic points in chemical equilibria
  • Explore advanced spectral analysis techniques for complex mixtures
  • Study the effects of pH on the absorbance spectra of phenolic compounds
USEFUL FOR

Chemists, students in analytical chemistry, and researchers involved in spectroscopic analysis of compounds will benefit from this discussion, particularly those focusing on the behavior of absorbance in varying chemical environments.

~christina~
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Difference Spectrum of 4-nitrophenol

Homework Statement


difference spectrum of 4-nitrophenol

Difference spectrum obtained has y-axis coresponding to \Delta Absorbance.
Consider shape and absorbance values over chosen range of wavelengths.

Use beer lambert relationship, explain why some absorbance values are:
a) > 0
b) < 0
c) at one \lambda \Delta Abs = 0

Hint:
1. What parameters in the beer lambert equation besides Absorbance is changing at each wavelength?
2. How does this affect the difference spectrum?


Homework Equations



A=abc

3. The Attempt at a Solution

graph descriptions of the y axis:
absolute basic graph 4-nitrophenol: the graph is above the x-axis and curves up from 0.07 - 0.48 and then curves downward from that point to -0.006.
absolute acidic graph: the graph is shaped like an exponential decay line. It starts at 0.265 and then goes downwards to 0.012 and then just goes along the x-axis until hitting 0
basic-acidic difference graph:
The graph looks exactly like the absolute basic graph except that the graph line has shifted downwards towards the (-) axis. The line of the curve going upwards (same as basic)
starts below the x-axis at -0.07 and then curves upwards and goes through the x-axis at 0. Then it hits 0.25 and then curves downwards from there all the way to 0.01 and then proceeds to go along the x-axis close to 0.


I know that the difference spectrum is basically the basic 4-nitrophenol spectrum (looks like exponential decay) - basic spectrum (looks like a curve going up).
But I'm not sure how to explain why some values are below 0, greater than 0, or are = 0.

I know that when Abs= 0 there is 100% transmittance of the light going through the solution.
Also know that at Isosbestic point (where the basic and acid graphs intersected at the beginning of the curves) was where the molar absorptivity (a) was the same for both the species. Is this the reason that the \Delta Abs= 0 was at about the same x value on the graph difference graph? (close to it about 350 vs 346) I do think it has something to do with it but I'm not sure. (Where the graphs of the absolute spectra intersected, that was the same place that the basic-acidic graph spectra's line went through the zero point of the graph)

I can't explain why using beer's law, how come some values on the difference graph are below 0 and some are above 0. All I can say is that the difference of the spectra caused this, but I don't know how to explain it using beer's law.

Help please
 
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~christina~ said:

Homework Statement


difference spectrum of 4-nitrophenol

Difference spectrum obtained has y-axis coresponding to \Delta Absorbance.
Consider shape and absorbance values over chosen range of wavelengths.

Use beer lambert relationship, explain why some absorbance values are:
a) > 0
b) < 0
c) at one \lambda \Delta Abs = 0

Hint:
1. What parameters in the beer lambert equation besides Absorbance is changing at each wavelength?
2. How does this affect the difference spectrum?


Homework Equations



A=abc

3. The Attempt at a Solution

graph descriptions of the y axis:
absolute basic graph 4-nitrophenol: the graph is above the x-axis and curves up from 0.07 - 0.48 and then curves downward from that point to -0.006.
absolute acidic graph: the graph is shaped like an exponential decay line. It starts at 0.265 and then goes downwards to 0.012 and then just goes along the x-axis until hitting 0
basic-acidic difference graph:
The graph looks exactly like the absolute basic graph except that the graph line has shifted downwards towards the (-) axis. The line of the curve going upwards (same as basic)
starts below the x-axis at -0.07 and then curves upwards and goes through the x-axis at 0. Then it hits 0.25 and then curves downwards from there all the way to 0.01 and then proceeds to go along the x-axis close to 0.


I know that the difference spectrum is basically the basic 4-nitrophenol spectrum (looks like exponential decay) - basic spectrum (looks like a curve going up).
But I'm not sure how to explain why some values are below 0, greater than 0, or are = 0.

I know that when Abs= 0 there is 100% transmittance of the light going through the solution.
Also know that at Isosbestic point (where the basic and acid graphs intersected at the beginning of the curves) was where the molar absorptivity (a) was the same for both the species. Is this the reason that the \Delta Abs= 0 was at about the same x value on the graph difference graph? (close to it about 350 vs 346) I do think it has something to do with it but I'm not sure. (Where the graphs of the absolute spectra intersected, that was the same place that the basic-acidic graph spectra's line went through the zero point of the graph)

I can't explain why using beer's law, how come some values on the difference graph are below 0 and some are above 0. All I can say is that the difference of the spectra caused this, but I don't know how to explain it using beer's law.

Help please


I haven't actually done any experiments with this concept , from the hint , I'm guessing it is directing you to investigate the fact that the molar absorptivity is distinct at each wavelength ... the particular atom involved in the functional group has varying degrees of molar absorptivity corresponding to various wavelengths and this attribute can be altered by either deprotonating it or protonating it or groups that are nearby.

What is the x axis? Is this a titration of some sort - I'm guessing not - what is meant by basic and acidic graphs?
 

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