Why Do Certain Answers Apply in Basic Electric Field Questions?

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SUMMARY

The discussion focuses on the correct answers to basic electric field questions, specifically question 16 and question 30. In question 16, the correct answer is E, as it relates to the uniform charge distribution and the resulting electric field, while choice D fails to account for the nature of the distribution. For question 30, the correct answer is A, determined by the relationship between voltage and electric field magnitude, specifically using the formula |E| = |ΔV/Δs| to identify where this ratio is maximized.

PREREQUISITES
  • Understanding of electric field concepts
  • Familiarity with uniform charge distributions
  • Knowledge of voltage and electric potential relationships
  • Ability to apply the formula |E| = |ΔV/Δs| in problem-solving
NEXT STEPS
  • Study the principles of electric fields in uniform charge distributions
  • Learn how to apply the formula |E| = |ΔV/Δs| in various contexts
  • Explore the implications of voltage differences on electric field strength
  • Review common mistakes in interpreting electric field questions
USEFUL FOR

Students studying electromagnetism, educators teaching electric field concepts, and anyone preparing for physics examinations focused on electric fields and potentials.

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Homework Statement


I'm confused about [question 16](http://image.prntscr.com/image/41a5c611927c44a7ac30104be3dd10ee.png) and [question 30](http://image.prntscr.com/image/a6aea3b9a8f04df9aca0dfe14054d4ce.png). The correct answers are e and a respectively.

Homework Equations

The Attempt at a Solution



For 16, why did D not work? Intuitively, I chose E because of parallel plates that have equal electric fields, but what is the integral for choice D and E and why are they different?

For 30, I thought higher voltage meant higher potential so I thought the answer should be C and D. Why is it A?
 
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16. The graph shows a uniform charge distribution, independent of x. Consider the charge distribution described in D. What does it look like? What do you know about the electric field that results from such a distribution?

30. You need to consider only one thing. The magnitude of the electric field can be approximated by ##|\vec{E}|=|\frac{\Delta V}{\Delta s}|##. Where is this ratio the greatest?
 

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