Why Do Different Methods Yield Different Spring Constants in Physics Problems?

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Homework Statement


A block of mass M is hung on a vertical spring.
We have to find spring constant k, x (displacement from mean position) given.

Homework Equations


1/2kx^2 = mgx
mg=kx

The Attempt at a Solution


When i conserve energy,
1/2kx^2=mgx
⇒ k= 2mg/x

But when i use mg=kx,
I get k=mg/x

But mg/x≠2mg/x,
Help please :)
 
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You don't need to compute energy here.
Just use Hooke Law directly.

What force is M applying to the spring?
How far is this causing the spring to stretch?

The assumption here is that the system is stable at x.
 
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.Scott said:
You don't need to compute energy here.
Just use Hooke Law directly.

What for is M applying to the spring?
How far is this causing the spring to stretch?

The assumption here is that the system is stable at x.
after that it is given some velocity v from down, i need to calculate how high will it go.
i used 1/2kx2=1/2mv2 is it correct?
 
I love physics said:
i used 1/2kx2=1/2mv2 is it correct?
Is that based on some reasoning or just a wild guess?

If it rises above the equilibrium point by a maximum of h, what are the changes in
  1. KE
  2. GPE
  3. Elastic PE
?
 
Consider the situation of the mass moving horizontally along a frictionless surface.
What is the difference in the two situations?