malawi_glenn
Science Advisor
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The usual treatment of the diamagnetism of atoms and ions employs the Larmor theorem: In a magnetic field the motion of the electrons around a central nucleus is, to the first order in B, the same as a possible motion in the absence of B except for the superposition of a precession of the electrons with angular frequency:
\omega = eB/2mc
This was from Kitell, diamagnetism is due to atomic electrons tending to loop around the applied B-field, i.e it is related to their orbital angular momenta. And they are orbiting so that the applied B field is canceled (not completley).
Paramagnetism is the tital Atomic spin J that wants to be allinged with the B-field.
Pauli paramagnetism is due to the conduction electrons intrinsic spin wanting to be allinged with the applied B-field.
Iam not going to write in this thread more, you are just annoying me grandpa. Cite scienfic litterature instead of coming with your non-sence speculations here. Superconductivity and diamagnetism are very well understood. You just seem to lack the basics.
Just read this:
"i know that. the question becomes why do they not form these cooper pairs in non-superconductors?"
Maybe becase cooper pairs gives you SC ?
\omega = eB/2mc
This was from Kitell, diamagnetism is due to atomic electrons tending to loop around the applied B-field, i.e it is related to their orbital angular momenta. And they are orbiting so that the applied B field is canceled (not completley).
Paramagnetism is the tital Atomic spin J that wants to be allinged with the B-field.
Pauli paramagnetism is due to the conduction electrons intrinsic spin wanting to be allinged with the applied B-field.
Iam not going to write in this thread more, you are just annoying me grandpa. Cite scienfic litterature instead of coming with your non-sence speculations here. Superconductivity and diamagnetism are very well understood. You just seem to lack the basics.
Just read this:
"i know that. the question becomes why do they not form these cooper pairs in non-superconductors?"
Maybe becase cooper pairs gives you SC ?