Once I saw a nice experiment where the experimentator used a high voltage power supply and compared the effect with and without an electric shield on the outlet of the water pipe, so that drops could form in field free space. The deflection of the drops was gone once the shield was employed which lead the experimentators to the conclusion that it is due to influence when the water droplets are formed and not due to the dielectric properties of the water drops. With a jet of water instead of droplets, influence should be even more important. Nevertheless, I tried to estimate the relative size of the two effects. When a water droplet of radius r forms at height l and transversal distance d < l over a point charge q, the influenced charge is of order of magnitude ##qr^2/l^2##. The relevant maximal force will act on it when it is at the same height as the charge, so that the distance is d. Then the force will be of magnitude ## F_i \sim qr^2/(l^2 d^2)##. On the other hand, the dielectric constant of the water droplet (epsilon=81) is very large. If we set it to infinity, the droplet behaves like a metallic sphere whose dipole moment can easily be calculated. The maximal force on the drop due to the charge-induced dipole moment interaction is ##F_d \sim q r^3/d^5##. So their ratio is ##F_d/F_i \sim r l^2/d^3##. In experiments where ##d \approx l##, the dipole force is smaller due to $$r \ll d\approx l$$. This seems to be the case, when a rubber globe is used as charge. In cases, where a charged rubber rod is used, d is considerably smaller than l, and both effects may be important. It would be interesting to do this experiment with an AC high voltage charge source of few kHz, as the deflection of charged drops should vanish in the AC field, while the interaction with the induced dipoles should remain unchanged.