Why Does a Positive Charge q Seem to Lose Kinetic Energy in the Diagram?

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SUMMARY

The discussion centers on the apparent contradiction between the text and the diagram regarding the kinetic energy of a positive charge q in an electric field. The text states that the positive charge gains kinetic energy as it moves towards the negative plate, while the graph indicates a loss of kinetic energy. The confusion arises from the interpretation of the graph's axes, where "falling" is interpreted as movement towards x = 0, suggesting that the labels for kinetic energy (K) and potential energy (U) may be incorrectly assigned if time progresses to the right.

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Miike012
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Look inside the paint doc.
My question is why does the paragraph say ...A positive charge q gains kinetic energy as it falls towards the negative plate...

However the graph shows that the positive charge q loses kinetic energy...

I am confused what am I not understanding?
 

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"Falling" appears to mean going toward x = 0, i.e. going left in the graph.
 
I think the U and K labels are the wrong way round in the diagram if time is increasing to the right. K should be increasing and U should be decreasing if a charge starts at rest on one of the plates and accelerates to the other - which is what the written passage says.
 

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