Why Does a System Behave as if It Has a Larger Mass in Water Compared to Air?

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SUMMARY

The discussion centers on the apparent increase in mass of a system moving in water compared to air, as observed during a lab on damped oscillations. Participants referenced Newton's 2nd Law, specifically the equation m = F/a, to analyze the differences in acceleration (a) between the two mediums. The resistance and buoyancy effects in water significantly alter the system's dynamics, leading to the perception of a larger mass. This phenomenon is attributed to the greater drag force experienced in water, which affects the acceleration and, consequently, the calculated mass.

PREREQUISITES
  • Understanding of Newton's 2nd Law of Motion
  • Basic principles of fluid dynamics
  • Knowledge of damped oscillations
  • Familiarity with measuring forces and accelerations in different mediums
NEXT STEPS
  • Study the effects of buoyancy on mass measurements in fluids
  • Explore the principles of drag force in different mediums
  • Learn about oscillatory motion in fluids versus air
  • Investigate experimental setups for measuring mass in various environments
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Physics students, educators, and researchers interested in fluid dynamics, oscillatory systems, and the application of Newton's laws in different environments.

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Homework Statement


This problem was presented as part of a lab write up. In the lab we were studying damped oscillations. We were asked to determine the mass indirectly based on values that we measured then compare it to the actual masses. We found that the calculated masses were much greater than the actual masses. The question is:

Explain why the system, that was moving in water, behave as if it has a much larger mass than the same system moving in air?

The Attempt at a Solution



I realize that this is probably a really simple question but for some reason I just cannot figure out an answer, any help would be great.

Sorry if this is in the wrong place.
 
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I can only take an educated guess, not seeing your actual setup or details of the procedure.

From Newton's 2nd Law: m = F/a

How is "a" different in the water vs. in air?
 

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