Why does center of mass behave

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SUMMARY

The discussion centers on the behavior of the center of mass (CM) of extended objects, specifically how it follows a parabolic trajectory similar to that of a point mass, while the object itself may rotate around this point. The key takeaway is that the net external forces acting on the object determine the motion of the CM, as internal forces cancel out. The formula for the center of mass, M\vec{r}_{cm} = m_1 \vec{r}_1 + m_2 \vec{r}_2 + ..., illustrates how the CM can be treated as a point mass for the purposes of analyzing motion under external forces.

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  • Understanding of Newton's 2nd Law of Motion
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  • Basic knowledge of rotational dynamics
  • Ability to interpret vector equations in physics
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xailer
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Why when we throw an extended object like a baseball bat will the center of mass follow the same parabolic path that we expect for a smaller obeject like ball, while the bat itself will rotate around this ceneter of mass?

Why does center of mass behave like a simpler object?

thank you
 
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If you imagine that an extended body (mass = M) as a set of smaller mass elements (mass = m_1, m_2,...), Newton's 2nd law implies that F_{net} = M a_{cm}.

It goes like this. Start with the definition of center of mass:
M\vec{r}_{cm} = m_1 \vec{r}_1 + m_2 \vec{r}_2 \ ...

Now take the second derivative:
M\vec{a}_{cm} = m_1 \vec{a}_1 + m_2 \vec{a}_2 \ ...

From Newton's 2nd law applied to each mass element, recognize that:
M\vec{a}_{cm} = \vec{F}_1 + \vec{F}_2 \ ...
M\vec{a}_{cm} = \vec{F}_{net} = \vec{F}_{external}

Note that internal forces cancel out and only external forces count. This can be summarized by saying that the cm of an object (or collection of particles) moves as though all the mass were concentrated at the cm and all the external forces were applied at that point.

(For more details, consult any first year physics text.)
 
What does a_{cm} mean? Acceleration of a part of an object that is 1 cm in length?

If that is the case, then M\vec{r}_{cm} must mean torque of a part of the body that is 1 cm in length?

Doc Al said:
M\vec{r}_{cm} = m_1 \vec{r}_1 + m_2 \vec{r}_2 \ ...
Isn't that a formula for finding how far from the rotation axis a center of mass is? Aren't rotational and translational movements two different things. I don't see how you can combine the two if that is what you are doing here

Note that internal forces cancel out and only external forces count.
what would internal forces be in this case?

This can be summarized by saying that the cm of an object (or collection of particles) moves as though all the mass were concentrated at the cm and all the external forces were applied at that point.
I'm sorry but I can't seem to be able to see the connection

(For more details, consult any first year physics text.)
I did and they don't answer my questions
 
xailer said:
What does a_{cm} mean? Acceleration of a part of an object that is 1 cm in length?

If that is the case, then M\vec{r}_{cm} must mean torque of a part of the body that is 1 cm in length?

No, the subscript "cm" stands for "center of mass".

Isn't that a formula for finding how far from the rotation axis a center of mass is? Aren't rotational and translational movements two different things. I don't see how you can combine the two if that is what you are doing here

No, that's the formula for locating the center of mass.

what would internal forces be in this case?

It could be anything that results in zero net force: Gravitational attraction, a string that connects the two masses, whatever.
 

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