Why Does Coulomb's Law Give Different Results for the Same Charges?

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SUMMARY

The discussion centers on the calculation of net forces acting on three charged objects: A (-4x10^-6 C), B (-6x10^-6 C), and C (+9x10^-6 C), spaced 0.5m apart. The user calculated the forces as Fba = 0.864 N (right) and Fbc = 1.944 N (right), leading to a net force of 2.8 N (right). The confusion arises from a discrepancy with the textbook's values, specifically regarding the direction of the force between B and C, which the user believes should be attractive due to opposite charges. The conclusion indicates a potential error in the textbook, suggesting a misprint or misreading of the charge signs.

PREREQUISITES
  • Understanding of Coulomb's Law and electrostatic forces
  • Basic knowledge of charge interactions (attraction and repulsion)
  • Ability to perform vector addition of forces
  • Familiarity with scientific notation for charge values
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  • Review Coulomb's Law and its applications in electrostatics
  • Learn about vector addition in physics to resolve forces
  • Examine common misconceptions regarding charge interactions
  • Investigate potential errors in physics textbooks and how to identify them
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Students studying electrostatics, physics educators, and anyone seeking to clarify concepts related to electric forces and charge interactions.

anna sung
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Homework Statement

three objects carrying charges of (a)-4x10^-6 C, (B)-6x10^-6 C, and (c)+9x10^-6 C are placed in a line equally spaced from left to right by a distance of 0.5m. calculate the magnitude and direction of the net force acting on each.

Homework Equations



Force of the magnitude of B(-6x10^-6 C) the answer is 1.08N left
but I am getting 2.8N right

The Attempt at a Solution



Fba= 0.864 N (right)
Fbc = 1.944 N (right)

fnet = 0.864N (right) + 1.944N (right)
= 2.8N right

i don't understand how the book got 1.944N (left) because that's what gives 1.08(left)

B is negative and C is positive so shouldn't B be attracted to C which is to the right?
please help me .
 
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anna sung said:

Homework Statement




three objects carrying charges of (a)-4x10^-6 C, (B)-6x10^-6 C, and (c)+9x10^-6 C are placed in a line equally spaced from left to right by a distance of 0.5m. calculate the magnitude and direction of the net force acting on each.

Homework Equations



Force of the magnitude of B(-6x10^-6 C) the answer is 1.08N left
but I am getting 2.8N right

The Attempt at a Solution



Fba= 0.864 N (right)
Fbc = 1.944 N (right)

fnet = 0.864N (right) + 1.944N (right)
= 2.8N right

i don't understand how the book got 1.944N (left) because that's what gives 1.08(left)

B is negative and C is positive so shouldn't B be attracted to C which is to the right?
please help me .

As you realize, the only way to get that is if the charge on C is the same sign as the charge on B.
Either you have mis-read, or they have mis-printed.
 

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