Why does current lag behind voltage in inductor?

Click For Summary
SUMMARY

The discussion centers on the phenomenon of current lagging behind voltage in inductors, specifically in alternating current (AC) circuits. Participants explain that inductors resist changes in current due to their magnetic fields, resulting in a 90-degree phase difference between voltage and current. The relationship is mathematically expressed as V(L) = L di/dt, indicating that voltage is proportional to the rate of change of current. The conversation also touches on the concept of reactive resistance, or reactance, which is distinct from traditional resistance and is crucial for understanding AC circuit behavior.

PREREQUISITES
  • Understanding of AC circuit theory
  • Familiarity with inductors and their properties
  • Knowledge of phasors and complex numbers in electrical engineering
  • Basic grasp of Lenz's Law and electromagnetic induction
NEXT STEPS
  • Study the mathematical derivation of V(L) = L di/dt for inductors
  • Learn about the concept of reactance and its role in AC circuits
  • Explore the relationship between voltage and current in capacitors
  • Investigate the use of phasors for simplifying AC circuit calculations
USEFUL FOR

Electrical engineers, students studying circuit theory, and anyone interested in the dynamics of inductors in AC circuits will benefit from this discussion.

  • #91
jim hardy said:
what an interesting couple pages.

i'm not anti-math but am sympathetic toward those who struggle with it.

being mildly autistic, my awkwardness made math more difficult for me than it should have been. simple arithmetic mistakes scuttled many a calculus problem that i'd set up correctly but blew the evaluating part from a dropped sign or something.

result is i am real skeptical of formulas unless i can "feel" them.

when you're as dumb as me you have to work twice as hard as normal people and that's why i try to explain things simply - if it keeps somebody from giving up it's worthwhile.

for anybody stuggling with concept behind operator j ;
here's what i decided felt right:
multiplying by operator j shifts phase 90 degrees
multiplying twice shifts you 180 degrees,
which is exactly same as multiplying by -1
so obviously j is sqrt(-1) , for when you multiply it by itself you get -1 and that's a square root.
And of course it's imaginary because everybody knows negative numbers don't have square roots.

works for me. I'm no Euler.
but i learn from most everybody i meet.
great discussion guys , thanks.

old jim

Well you are "dumb" as I am. Because I can only work with formulas if I can "feel" them too. Mathematical and physical ones, both I have to "feel".
 
Engineering news on Phys.org
  • #92
I'm not sure I have ever needed to "feel" math...just understand it.

To me math has come easy...but I certainly "feel" for those who trouble with it.

In alegebra there is one basic rule..."what you do to one side of the equation...you do to the other side".

That and there are only two things you can do in math...add or multiply.

Subtracting is addition of the opposite...division is multipication of the reciprical.

And yes, there are a ton of little rules, but the above is pretty much the basics...I "feel".
 
  • #93
'multiply' is just a series of additions, in any case.
But ordinary arithmetic rules are not used in all maths - so there is a tiny bit more to it. :cool:
 
  • #94
I agree.

You can certainly go far with the basics I mentioned...differetial equations, calc 3 and so on.

But yes...it is a bit more complicated.

And actually the math is simple eventually...learning how to set up the problems in real life...or in story problems is the trick.
 

Similar threads

Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
7K
Replies
10
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K