So in projectile motion, an object launched horizontally traveling over a certain displacement (Δx), fall time remains constant regardless of what this horizontal velocity was.(adsbygoogle = window.adsbygoogle || []).push({});

I understand that in this equation:

Δx = v(avg) × Δt

as horizontal velocity increases, displacement also increases, with time serving as the constant of variation. Mathematically, this makes sense. But in reasoning, I'm having a hard time grasping the concept. Just why does time remain constant?

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# Why does drop time remain constant regardless of initial horizontal velocity?

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