Why Does Hooke's Law Consider Only 150N in a Two-Person Pull Test?

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SUMMARY

The discussion centers on Hooke's Law and its application in a two-person pull test involving a light spring with a spring constant of 756 N/m. When two individuals pull the spring with forces of 150 N each, the total force is 300 N; however, the effective extension of the spring is calculated based on the opposing forces, resulting in a length of 0.54 m. The confusion arises from the interpretation of forces as vectors, where the net force on the spring is zero, leading to the conclusion that only one side's force is considered in the calculation.

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  • Understanding of Hooke's Law (F = kx)
  • Basic knowledge of spring mechanics
  • Familiarity with force vectors and equilibrium
  • Ability to perform calculations involving mass, weight, and spring constants
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  • Study the implications of force vectors in mechanical systems
  • Learn about the principles of static equilibrium in physics
  • Explore advanced applications of Hooke's Law in real-world scenarios
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the practical applications of Hooke's Law in spring dynamics.

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Homework Statement



Hooke's law describes a certain light spring of unstressed length 35.0 cm. When one end is attached to the top of a door frame and a 5.40 kg object is hung from the other end, the length of the spring is 42.00 cm.
(a) Find its spring constant.



(b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 150 N. Find the length of the spring in this situation.



Homework Equations



F=Kx

The Attempt at a Solution



A)
The spring constant is equal to
mg=kx
5.40*9.8=k*(.42-.35)
52.92=k(.07)
k=756 Nm

B)
∑F=150+150=300
300=kx
300/k=x
x=.39m

.39+.35=.74m

Which according to the book the correct answer is .54m which I was able to get if I only accounted for 150N being pulled instead of 300N since 150N is being pulled from both sides of the spring. I don't understand why it would only be 150N?
 
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Consider - when it was haging from the door, the weight pulled it by mg and the door pulled in the opposite direcetion by mg, yet you didn't say that kx=2mg did you? Why not?

Replace one of the people by a pole stuck in the ground - you get 150N one way due to the other person, and 150N the other way from the pole.

Note: force is a vector - so the total force on the spring is actually zero.
 

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