Why Does Mass Positioning Affect Weight Discrepancies in Suspended Systems?

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Homework Help Overview

The discussion revolves around the effects of mass positioning on weight discrepancies in suspended systems, specifically focusing on a ruler suspended from a point and how the placement of mass influences the forces experienced at different points along the ruler.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are exploring the relationship between mass placement and the resulting forces at different points on the ruler. Questions arise regarding the definitions of torque and force, as well as the implications of moving mass closer to the suspension point.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the concepts of torque and force. Some have expressed confusion about the original question and its implications, while others are attempting to relate the mathematical relationships involved.

Contextual Notes

There are indications of misunderstandings regarding the setup of the problem, particularly concerning the suspension point and the effects of mass placement on torque. Participants are also referencing specific formulas related to torque, suggesting a focus on the mathematical aspects of the problem.

Ry122
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A ruler is suspended from point x. When a mass is put at point y the mass at x is heavier than when it is at point p.
x-------------------p------------------------y
------------------------------------------------
Why is it that when the mass is moved closer to x the mass at x decreases?
 
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do you mean force?
 
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
[tex]\tau =rXF[/tex]
So at X the value of r is nil.
 
Last edited:
Sorry Tau=rXf
 
i.mehrzad said:
I did not understand the question properly.
You mention that the ruler is suspended from the Point X which is the leftmost point then what effect will the mass have when it is put at the suspension point.

Just to put it into perspective.
Note
[tex]\tau =rXF[/tex]
So at X the value of r is nil.

yes which means the force at y is zero but the force at x is max
 
Thanks for the help but what I really wanted to know was why t=r x f. I can understand that the torque increases when the force is increased but why is it that when r increases the torque increases?
 

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