- #1
jaumzaum
- 434
- 33
If we consider that the heating of the products created in the combustion of paper to be an almost adiabatic process (as it's extremely fast), then
$$T^{1.4} P^{-0.4} = const. $$
If we double the temperature, we multiply the pressure by 11.3
The density of an ideal gas is
$$ \rho=PM/RT$$
If we double the temperature, the density would be multiplied by 5.7
So why would the smoke rises if it became more dense?
$$T^{1.4} P^{-0.4} = const. $$
If we double the temperature, we multiply the pressure by 11.3
The density of an ideal gas is
$$ \rho=PM/RT$$
If we double the temperature, the density would be multiplied by 5.7
So why would the smoke rises if it became more dense?