Why Does the Block Not Reach the Expected Distance on the Incline?

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SUMMARY

The discussion revolves around the mechanics of a block launched by a spring gun up an incline. The block's motion is analyzed using energy equations, specifically focusing on the spring constant (k), mass (m), gravitational acceleration (g), incline angle (theta), and the coefficient of kinetic friction (mew). A participant expresses confusion over their derived equation for the distance (L) the block travels, particularly the inclusion of an additional variable (x) at the end of their expression. The community provides insights into correcting the energy balance and clarifying the role of friction in the calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with spring mechanics and Hooke's Law
  • Knowledge of energy conservation principles
  • Basic concepts of friction and inclined planes
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  • Review the principles of energy conservation in mechanical systems
  • Study the effects of friction on motion along inclined planes
  • Learn how to derive equations for motion involving springs and inclined surfaces
  • Explore advanced applications of Hooke's Law in real-world scenarios
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Students and professionals in physics, mechanical engineering, and anyone interested in understanding the dynamics of motion on inclined planes and the effects of friction on such systems.

kleencut
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Gun Shoots Block Up Incline!

1. A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x. The spring has spring constant . The incline makes an angle (theta) with the horizontal and the coefficient of kinetic friction between the block and the incline is mew. The block is released, exits the muzzle of the gun, and slides up an incline a total distance L.



2. Energy equations



3. I keep getting ;
((.5(k*x^2))/((m*g*sin(theta)+(mew*m*g*cos(theta)))+x

-- This answer is wrong and i don't understand why, I've worked it like 5 times and always get this answer. Please Help!
 
Last edited:
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Hi kleencut,

kleencut said:
1. A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x. The spring has spring constant . The incline makes an angle (theta) with the horizontal and the coefficient of kinetic friction between the block and the incline is mew. The block is released, exits the muzzle of the gun, and slides up an incline a total distance L.



2. Energy equations



3. I keep getting ;
((.5(k*x^2))/((m*g*sin(theta)+(mew*m*g*cos(theta)))+x

Maybe I'm just missing it, but I don't see what the problem is asking for?

In this last equation, you have an x at the very end of the expression. Can you show how you got that expression and that x?
 

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