Why Does the Block Not Reach the Expected Distance on the Incline?

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kleencut
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Gun Shoots Block Up Incline!

1. A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x. The spring has spring constant . The incline makes an angle (theta) with the horizontal and the coefficient of kinetic friction between the block and the incline is mew. The block is released, exits the muzzle of the gun, and slides up an incline a total distance L.



2. Energy equations



3. I keep getting ;
((.5(k*x^2))/((m*g*sin(theta)+(mew*m*g*cos(theta)))+x

-- This answer is wrong and i don't understand why, I've worked it like 5 times and always get this answer. Please Help!
 
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Hi kleencut,

kleencut said:
1. A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x. The spring has spring constant . The incline makes an angle (theta) with the horizontal and the coefficient of kinetic friction between the block and the incline is mew. The block is released, exits the muzzle of the gun, and slides up an incline a total distance L.



2. Energy equations



3. I keep getting ;
((.5(k*x^2))/((m*g*sin(theta)+(mew*m*g*cos(theta)))+x

Maybe I'm just missing it, but I don't see what the problem is asking for?

In this last equation, you have an x at the very end of the expression. Can you show how you got that expression and that x?