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Why does the free end refraction occur after Brewster's angle in TM?
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[QUOTE="jojoe, post: 6823637, member: 698012"] I think free end reflection might be proper representation, that the reflected light has the same phase with incident light. I thought about some idea that the reflection coefficient can be represented with the summation of free end reflection term(which has positive sign with cosine) and fixed end reflection term(which has negative sign of sine in sqrt). As the angle gets greater than Brewster angle, the free end reflection term is dominant, so the whole reflection terms gets positive value, which designates free end reflection of TM wave. Will it be related with the cancellation between the incident and reflected waves? [/QUOTE]
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Why does the free end refraction occur after Brewster's angle in TM?
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