Why does the integration of a function with a negative lambda result in -1?

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SUMMARY

The discussion centers on the integration of the function f(x) = -lambda * e^(-lambda * x) from 0 to infinity. The correct result of this integral is 1, while integrating lambda * e^(-lambda * x) yields -1. The confusion arose from neglecting the negative sign in front of lambda, which is crucial for obtaining the correct answer. Understanding this distinction is essential for accurate integration results in calculus.

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chrismariesan
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okay the problem asks to integrate this function from 0-infinity
i integrated but the answer i get is e^-lambdax from 0 to infinity
so e^0 is 1
and you will have 1-e^-lambda(x) where x is infinity
how does this come out to be -1?
please explain to me...i think i just forgot a rule
 
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Hopefully, you're integrating the function f(x) = -lambda*e^(-lambda*x), otherwise your answer is wrong. The integral of this from 0 to infinity is 1. If you are integrating lambda*e^(-lambda*x), then that is -1.
 
ok, i think i figured it out. i was completely ignoring the fact that it was a NEGATIVElambda (x). i realized this shortly after posting.
 

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