Why does the magnetic flux in a solenoid depend on the number of loops?

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SUMMARY

The magnetic flux in a solenoid is defined as B*N*A, where B is the magnetic field strength, N is the number of loops, and A is the cross-sectional area of each loop. This relationship arises because each loop contributes equally to the total magnetic flux, effectively summing the contributions of each individual loop. The concept is rooted in electromagnetic induction, where the induced electromotive force (emf) is proportional to the total change in magnetic flux across all loops. Thus, the total flux is not merely B times a single area A, but rather the cumulative effect of all N loops.

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yosimba2000
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In a solenoid of N loops and uniform magnetic field B, the magnetic flux is B*N*A, where A represents the area surrounded by each loop.

I see that the N comes from the fact that you have one A for each turn, and you have N turns, so the total "area" is NA, but why do we use this? Why isn't magnetic flux just equal to B times only one cross-sectional area A?

Is it just definition?
 
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Note that this is for a solenoid in an external field B. That the windings are stacked doesn't matter. If they were placed beside each other would you also have trouble with the expression ?

THere is some law that says that an emf is induced when the flux changes. In a coil all the emfs from the individual turns are added up, hence the factor N.
 
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yosimba2000 said:
In a solenoid of N loops and uniform magnetic field B, the magnetic flux is B*N*A, where A represents the area surrounded by each loop.

I see that the N comes from the fact that you have one A for each turn, and you have N turns, so the total "area" is NA, but why do we use this? Why isn't magnetic flux just equal to B times only one cross-sectional area A?

Is it just definition?

A solenoid is equivalent to a stack of loops of wire on top of each other. So if you have a flux for ONE loop, if you stack up N loops, why shouldn't the total flux be the sum of each individual flux?

Zz.
 

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