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I dont understand why it would not be in the +Y direction

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- #1

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I dont understand why it would not be in the +Y direction

- #2

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Upon applying a 90 degree pulse, the entire magnetization, (from the nuclear spins), that has been rotated away from the z-direction, is precessing around in the X-Y plane if I remember the result correctly. (The large static field in the z-direction causes this precession. The large static field in the z-direction is effectively cancelled only in the rotating frame. ## M \times B_z ## will supply the necessary torque to cause the precession.) During the application of the r-f signal at resonance in the x-direction, the magnetization vector is precessing around in the laboratory frame, while in the rotating frame, it appears to simply make a 90 degree rotation from the z-direction to the X-Y plane. The direction the magnetization rotates in the rotating frame can be readily computed. Hopefully your textbook correctly computed it.

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- #3

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Besides what I mentioned in post #2, there are a couple of additional items that might be of interest. One important item in the derivations is the relationship between the time derivative of a vector ## \vec{r} ## in the laboratory frame versus the rotating frame: ## [d \vec{r}/dt]_o=d \vec{r} /dt +\omega \times \vec{r} ##. One other item is that the angular momentum ## J ## from magnetization ## M ## is ## M=\gamma J ##, so that ## dJ/dt=M \times B ## becomes ## dM/dt=\gamma M \times B ##. It should be noted in the last equation, that the solution for ## M ## is that it rotates at frequency ## \omega=-\gamma B ## about the vector ## B ##. Notice from the first equation above that ## dM/dt=0 ## in the rotating frame (## M ## is constant), but ## [dM/dt]_o=\omega \times M ## in the laboratory frame.

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