Why Does Young's Double Slit Experiment Use n + 1/2 Instead of m - 1/2?

[nesan]

Homework Statement

Is this wrong or right? PLZ.

The Attempt at a Solution

http://www.kentshillphysics.net/optics36.gif

I have a test tomorrow buy my teacher said it's m - 1/2

Why does it say n + 1/2 everywhere. >_<

 

[Villyer]

What is m in this equation? (both according to your teacher and to the other sources you found)

 

[nesan]

What is m in this equation? (both according to your teacher and to the other sources you found)

According to my teacher n is the number of spots from the center (dark or light).

Here's one of my other source.

http://farside.ph.utexas.edu/teaching/316/lectures/node151.html

 

[Villyer]

From your source, m is an integer 0,1,2...
This means that the equation simplyfies into $(\frac{1}{2})\gamma =dsin(\theta)$, $(\frac{3}{2})\gamma =dsin(\theta)$, $(\frac{5}{2})\gamma =dsin(\theta)$...

From your teacher, the number of spots away from the center is n.

So the first spot would yield $(\frac{1}{2})\gamma =dsin(\theta)$, the second would be $(\frac{3}{2})\gamma =dsin(\theta)$, and the third would be $(\frac{5}{2})\gamma =dsin(\theta)$.

Do you see where I'm going with this?

 

[nesan]

From your source, m is an integer 0,1,2...
This means that the equation simplyfies into $(\frac{1}{2})\gamma =dsin(\theta)$, $(\frac{3}{2})\gamma =dsin(\theta)$, $(\frac{5}{2})\gamma =dsin(\theta)$...

From your teacher, the number of spots away from the center is n.

So the first spot would yield $(\frac{1}{2})\gamma =dsin(\theta)$, the second would be $(\frac{3}{2})\gamma =dsin(\theta)$, and the third would be $(\frac{5}{2})\gamma =dsin(\theta)$.

Do you see where I'm going with this?

Oh I got it. :)

Tnx. :)

<3