Why doesn't the electron fall into the nucleus?

In summary, the reason why the electron does not fall into the nucleus is due to its wave-like nature and the principles of quantum mechanics. The electron exists in a state of probability, constantly moving and occupying a space around the nucleus. This prevents it from collapsing into the nucleus, as it would violate the Heisenberg uncertainty principle. Additionally, the electron also possesses a negative charge, creating a repulsive force that counteracts the attractive force of the positively charged nucleus. These factors work together to keep the electron in a stable orbit around the nucleus.
  • #71


Thank you malawi glen.I should have searched first. I can be so dopey at times.

Thank you camboy.That looks brilliant.I just want a taster of what its all about and I think I have got that already just by looking at the opening bits.When I get time I will look at the rest.

And thank you alxm.I saw your message at the moment I posted this .I have to go now and I look forward to reading it later.
 
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  • #72


malawi_glenn said:
Same holds with R. Feynman quotes, as someone said "In physics, we don't have any prophets".

Suppose you lived in Amazon and you have never heard about Einstein's relativity or Schrodinger Equation. *** Can you figure it out by yourself? I doubt. That why they got Nobel prize but we don't
 
  • #73


feynmann said:
Suppose you lived in Amazon and you have never heard about Einstein's relativity or Schrodinger Equation. *** Can you figure it out by yourself? I doubt. That why they got Nobel prize but we don't

And the reason for they got Nobel prize was that other physicists can verify their results independently etc. Just because a guy who has got the Nobel Prize does not per automatic make him pass all peer reviews, everything has to be tested.

The person I quoted was Weinberg, if you know who that is ...

and your "analogy" is not even applicable, it is not the amazon tribe guys who give away Nobel Prizes.. LOL
 
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  • #74
alxm said:
At the moment, nobody has been able to come up with any real experiment to prove (or disprove) hidden variables (much less determine what they are). Many have tried. So the end result is that no interpretation is experimentally testable - or practically significant. There's no practical difference between having a system that's non-deterministic, and one that's deterministic but in terms of things that cannot be measured.

Still, 'hidden variables' is an appealing idea. The problem is with Bell's theorem, which didn't prove or disprove hidden variables, but experimentally (the famous Aspect experiment, etc) showed that if they exist, that they cannot be local. Which is also very weird. (in other words, a kind of faster-than-light interaction is going on).

I wouldn't agree with this statement. There are a number of very powerful experiments which disprove ALL hidden variable interpretations. Please keep in mind that advocates of some of these interpretations do not accept this evidence, and in some cases those same advocates assert they do not apply (for example Bohmians generally class BM/dbb theory as contextual and therefore these No-Go theorems don't apply). So I will let you form your own opinion. However, these are some of the recent proofs:

Experimental test of quantum contextuality in neutron interferometry: Test of the Kochen-Specker theorem.

http://www.iop.org/EJ/article/1367-2630/11/3/033011/njp9_3_033011.html: Hardy's.

Leggett's theorem without inequalities: Leggett's.

Comprehensive proof of the Greenberger-Horne-Zeilinger Theorem for the four-qubit system: Don't forget the GHZ theorem!

Mermin's 1990 summary on No-Go Theorems

So all of these are completely independent of Bell, and do not require the assumption of locality. Not trying to bait the Bohmians with these, as we know already they don't acknowledge any of it.
 
  • #75


DrChinese said:
I wouldn't agree with this statement. There are a number of very powerful experiments which disprove ALL hidden variable interpretations. Please keep in mind that advocates of some of these interpretations do not accept this evidence, and in some cases those same advocates assert they do not apply (for example Bohmians generally class BM/dbb theory as contextual and therefore these No-Go theorems don't apply).

So, in your opinion, what is the way to go? What are we to do with Schrodinger's cat?
 
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  • #76
  • #77


granpa said:
I'm not sure you understood me. here is what I was talking about:
https://www.physicsforums.com/showpost.php?p=1287217&postcount=8

(if we could think of the electron in the H atom as a continuous distribution of charge, it shouldn't radiate.)

--- Your above hydrogen atom model is so interesting, and points out an important thing.

But you forget one thing.
If the whole hydrogen atom is stopping still, it does not radiate as you say.
But actually the whole hydrogen atom is oscillating and moving about, So it loses energy by emitting electromagnetic waves in your model.
 
  • #78


the electron doesn't have to be motionless to not radiate. it just has to be smeared out over the whole orbit.

whether the hydrogen atom as a whole is moving or oscillating or not is irrelevant to the topic at hand which is 'why doesn't the electron fall into the nucleus'. I have no idea why you would even bring it up.

a mass of warm hydrogen atoms will indeed radiate heat radiation until it cools and the atoms are no longer moving. so what?
 
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  • #79


granpa said:
the electron doesn't have to be motionless to not radiate. it just has to be smeared out over the whole orbit.

Only electrons just don't act like that.

To begin with, the Thomas-Fermi model, and by extension, any such simple electrostatic model that assumes electrons have constant momentum, cannot form chemical bonds and stable molecules. That's even been rigorously mathematically proven. (The Thomas-Fermi theory of atoms, molecules and solids, EH Lieb, B Simon - Adv. Math, 1977)

There is no classical or semi-classical model of atoms that comes even close to being useful, even as an approximation.
 
  • #80


I don't know anything about the Thomas-Fermi model and I very much doubt its anything like what I'm describing.

what on Earth do you mean by 'constant momentum'? do you mean constant angular momentum?

and yes I am sure that chemical bonds (electron pairing) require a quantum mechanical explanation. so what? my point was simply to show how the electron can keep from falling into the nucleus

and now that I think about it, what do you mean 'electrons don't act like that'? that's pretty much what quantum mechanics is all about. the electron becomes smeared out over the whole atom due to the uncertainty principle.but these discussions go round and round and nothing is ever resolved. whatever your answers are there is nothing I can add at this point that others can't plainly see for themselves.
 
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  • #81


alxm said:
Personally, I'm mostly an adherent of malawi_glenn's quote: "Only amateurs concern themselves with interpretations". It makes no difference what interpretation you use. I don't even see why you'd bother thinking about it - unless it can be experimentally disproven, it's metaphysics or theology to me, and no more interesting than debating how many angels can dance on the head of a pin.

It was originally me. And I agree - until you can measure it, arguing about something can be many things, but science is not one of them.

I'd go further and say that fundamental question interpretations are asking is "what is happening when we aren't measuring anything"? Of course, by construction, this is unanswerable.

DrChinese said:
I wouldn't agree with this statement. There are a number of very powerful experiments which disprove ALL hidden variable interpretations.

I agree with this.
 
  • #82


granpa said:
I don't know anything about the Thomas-Fermi model and I very much doubt its anything like what I'm describing.

what on Earth do you mean by 'constant momentum'? do you mean constant angular momentum?

Sounds like a hasty conclusion if you don't know anything about it. And yes, it means both momentum and angular momentum. Such as would be the case with an electronic 'cloud' at a fixed distance, which seemed to be what you envisioning.


and yes I am sure that chemical bonds (electron pairing) require a quantum mechanical explanation. so what? my point was simply to show how the electron can keep from falling into the nucleus

But if you use an un-physical model to do so, it doesn't actually show anything.

and now that I think about it, what do you mean 'electrons don't act like that'? that's pretty much what quantum mechanics is all about. the electron becomes smeared out over the whole atom due to the uncertainty principle.

And that's part of the point I was making. If you think a quantum mechanical description of an bound electron simply means replacing a point charge with a static charge-density 'cloud', then you're simply wrong, because you have to account for the complicated dynamics of motion of the electrons. Even though the charge-density distribution is constant, electrons move, dynamically and have substantial kinetic energy. Any model based soley on electrostatic interactions is going to fail badly.
 
  • #83


alxm said:
And that's part of the point I was making. If you think a quantum mechanical description of an bound electron simply means replacing a point charge with a static charge-density 'cloud', then you're simply wrong, because you have to account for the complicated dynamics of motion of the electrons. Even though the charge-density distribution is constant, electrons move, dynamically and have substantial kinetic energy. Any model based soley on electrostatic interactions is going to fail badly.
This isn't suggesting that electrons "move" continuously, right?
 
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  • #84


I find this very interesting, and the term electron cloud, I really like.

Because I only have a limited understanding of all this, I try to build a picture in my mind of something large enough to interact with, in this case I see the atom the size of a golf ball. At this size if we take an atom (say copper) with a single electron in the outer shell, the speed of the outer electron circling the nucleus, by rough math, is over 120 billion revolutions per second. At this size the electron and nucleus will still be too small to see, in fact the outer shell would be invisible, but feel like a solid object.

The question I have is, has anyone ever purposed a therory of air or a gas like substance being bound inside the valence shell, and equally divided between the other shells, I see this like compressed air inside a basketball. Heat would have an effect and an expansion and contraction would take place.
At the speed an electron moves, it seems a seal barrier might exist, and all shells would react to any energy change.

Just a thought that popped into my brain as I was reading through the thread, I did look at some other threads that had been linked by Marlon (I think). One of those threads mentioned "Kato's Theorem" but I have not found anything yet.

Don't worry, I'm sure this will be my only post here.:wink:

Ron
 
  • #85


Vanadium 50 said:
It was originally me. And I agree - until you can measure it, arguing about something can be many things, but science is not one of them.

That is one of my favourite quotes of all times :!)
 
  • #86


RonL said:
The question I have is, has anyone ever purposed a therory of air or a gas like substance being bound inside the valence shell, and equally divided between the other shells, I see this like compressed air inside a basketball. Heat would have an effect and an expansion and contraction would take place.
At the speed an electron moves, it seems a seal barrier might exist, and all shells would react to any energy change.

Ron
Hi RonL,

The thing you appear to have overlooked is that "air" is made of molecules, which are themselves composed of atoms.

It's counter-intuitive but a bound electron is not stationary. And it's not moving either.
 
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  • #87


DrChinese said:
I wouldn't agree with this statement. There are a number of very powerful experiments which disprove ALL hidden variable interpretations.

You don't mean to say local hidden variable? Even unlocal hidden variable interpretations have been disproven? I was unaware of this.
 
  • #88


WaveJumper said:
Hi RonL,

The thing you appear to have overlooked is that "air" is made of molecules, which are themselves composed of atoms.

It's counter-intuitive but a bound electron is not stationary. And it's not moving either.

Thanks for the reply,
The mention of "air or gas like substance" was only to help build a thought.

I'm a long way from knowing enough to throw anything else out, but when I read about density of black holes, my little pea brain thinks something has to fill the voids from the nucleus to the outer shell.:redface:

Guess I better get back to things i can see.:biggrin:
 
  • #89


WaveJumper said:
Hi RonL,

The thing you appear to have overlooked is that "air" is made of molecules, which are themselves composed of atoms.

It's counter-intuitive but a bound electron is not stationary. And it's not moving either.

What about particle in a box? http://en.wikipedia.org/wiki/Particle_in_a_box
<Particle in a box> is a bound state and its potential energy is all zero.
It's absurd to suggest that it's Not moving in the box. What else can it do in the box, just sit there?
 
  • #90


feynmann said:
What about particle in a box? http://en.wikipedia.org/wiki/Particle_in_a_box
<Particle in a box> is a bound state and its potential energy is all zero.
It's absurd to suggest that it's Not moving in the box. What else can it do in the box, just sit there?

You have to define pecisely what you mean by "moving". So, you need to write down some observable, e.g. the momentum operator, and look at the expectation value. In case of a particle in a box in some energy eigenstate, the expectation value of the momentum is zero. The particle in an energy eigenstate is in a superposition of two states with opposite momenta.
 
  • #91


RonL said:
The question I have is, has anyone ever purposed a therory of air or a gas like substance being bound inside the valence shell, and equally divided between the other shells, I see this like compressed air inside a basketball. Heat would have an effect and an expansion and contraction would take place.
Ron

that was my first thought too. but the electron is a single indivisible particle. if it seems odd to you that it can be a single indivisible particle and at the same time be spread out over an entire orbital then it shouldnt. it can even be spread out simultaneously over several orbitals (as when it is absorbing or emitting light). that's called 'superposition'.
 
  • #92


feynmann said:
So, in your opinion, what is the definition of moving?

In quantum mechanics, it makes sense to define a particle to be moving if it is described by some wavepacket. It then has an approximate position and momentum. You can also argue that since a plane wave represents a particle with precisely determined momentum, such a state should also be considered to be "moving". However, in that case, the state is not evolving in time (apart from a phase factor).

Thing is that you can't separately specify momentum and position in quantum mechanics. Once you've specified all the mometum components of a state, the state is completely fixed; all the position components of the state thus fixed.

In classical physics you can consider momentum and position to be completely independent. Our notion of "motion" is grounded in classical physics, so it is not a well defined concept to start with.

It is similar to building a house out of bricks and then looking at the house from some distance so that you don't see the individual bricks anymore. You can make all sorts of objects with different shapes out of bricks. But if you look closely and you see the individual bricks you will be constrained in what shapes you can make. You can only make 90 degree turns, so smooth curves do not exist at this level.

Similarly, we can build a state that looks like a particle moving from one position to another by making a wavepacket. If you look at it from a large length scale and you cannot resolve the width of the wavepacket, you see what looks like a particle that seems to have a definite position which is moving at a definite velocity.

But what we see is an illusion. The laws of physics forbid that such a state could exist at all. Yet, we have defined the very concept of motion to refer to exactly such a state.
 
  • #93


granpa said:
that was my first thought too. but the electron is a single indivisible particle. if it seems odd to you that it can be a single indivisible particle and at the same time be spread out over an entire orbital then it shouldnt. it can even be spread out simultaneously over several orbitals (as when it is absorbing or emitting light). that's called 'superposition'.

My thought stemed from the many times i have looked at something through a spinning prop, and knowing from experience that a dense object will not pass through a shop fan. The electron has small mass and due to it's velocity, is spread all around the shell area as though it were a solid wall. If any substance exist that fills spaces between shells down to the nucleus, it seems that the movements might be somewhat like our upper atmosphere, where layers move past each other yet do not mix.

I feel that a thought is the start of any learning process, for me, I'm sure I'll look back at this in the future and sink a little lower in my chair, or it might be the start of something special:biggrin: for me at least.
 
  • #94


you are talking as though the electron shell were hollow. it isnt.
 
  • #95


granpa said:
you are talking as though the electron shell were hollow. it isnt.

WELL, that sure changes things:eek:
 
  • #96


Count Iblis said:
You have to define pecisely what you mean by "moving". So, you need to write down some observable, e.g. the momentum operator, and look at the expectation value. In case of a particle in a box in some energy eigenstate, the expectation value of the momentum is zero. The particle in an energy eigenstate is in a superposition of two states with opposite momenta.

It should be noted that any stationary state will have an expectation value of zero for the momentum. Eigenstates for the particle in a box, hydrogen atom, etc. derived from the time-independent Shroedinger equation will all have zero expectation value for the momentum.
 
  • #97


Matterwave said:
You don't mean to say local hidden variable? Even unlocal hidden variable interpretations have been disproven? I was unaware of this.

As you say, the generally accepted view is that there can be no successful local hidden variable theories. I generally stick to the solid stuff (such as Bell). However...

I would say we are very close to the point where even non-local HV theories will be generally considered as "no-go". Now, if we want to debate the underlying validity of the science, that belongs in another thread. And I am not advocating this position anyway, as there is currently a lot of controversy in the area. But there is a LOT more that just a few papers on the subject. And there is a LOT more that just a few people who have already come to this conclusion. The conclusion being based on the following approaches: Kochen-Specker, GHZ, Hardy and Leggett. So my answer is based on my opinion of where the scientific winds are blowing. And I think that HV candidates will have a tough time against these.

Now for the Bohmians: I personally am very interested in finding the best answers to these and other questions about non-locality as an approach. Honestly, it is the most "logical" explanation. And I realize that Bohmians do not consider theirs a non-contextual theory (although I do because it claims to be deterministic). We are lucky to have several top-notch Bohmian theorists on this board, and I think their contributions are very exciting. So I certainly hope no one takes offense because I am not trying to stir up a hornet's nest.

But my opinion doesn't really matter anyway, what I am really saying is that the scale is in the process of tipping in the view of the scientific community at large - and I consider this a relatively new development. If this were a boxing match: I would be hoping I had bet against HV approaches. But the match is not yet over, and I expect there will be a lot of relevant interesting papers coming out in the few years. :smile:
 
  • #98


WaveJumper said:
This isn't suggesting that electrons "move" continuously, right?

They're in constant motion, yes. But they don't move continuously as in 'a continuous path', no. But that much has already been established when saying they don't have a definite location.

See, there's a very common pedagogical problem here. First people learn about the Bohr model and how that's wrong - the electrons don't have a definite location, and are instead described by a location-probability distribution (orbital).

It's then easy, and very common, to make the mistake of thinking that that's the whole picture - that the electron isn't moving, but is stationary - because the probability distribution is stationary. But that would only be half the picture. They still move. Just not in continuous paths. There's no accounting for purely dynamical effects such as correlation energy (the effect on kinetic energy from the correlated motions of electrons), unless you actually think of them as moving.

Is it conceptually difficult to reconcile the idea that the thing is moving, yet has a constant distribution of location-probabilities? Yes. But that's just quantum mechanics for you. Neither particle nor wave, you know.
 
  • #99


alxm said:
Is it conceptually difficult to reconcile the idea that the thing is moving, yet has a constant distribution of location-probabilities? Yes. But that's just quantum mechanics for you. Neither particle nor wave, you know.

How is it conceptually difficult? You can take an analogy to be the motion of a particle oscillating on a pendulum. The probability of measuring the particle at some point at some random time will be constant yet the thing is moving. The probability density is greatest at the turning points of oscillation and is minimum at the equilibrium point.
 
  • #100


thoughtgaze said:
How is it conceptually difficult? You can take an analogy to be the motion of a particle oscillating on a pendulum. The probability of measuring the particle at some point at some random time will be constant yet the thing is moving. The probability density is greatest at the turning points of oscillation and is minimum at the equilibrium point.

These two statements that I highlighted appear to be contradictory to each other.

The reason why the scenario is conceptually difficult is that it makes OTHER issues difficult. A pendulum has its bob a specific location as a specific time, not spread out all over its trajectory, the latter of which is the conventional picture adopted by standard QM. And there ARE consequences of such a scenario, ranging from molecular bonds, to the existence of the coherent gap in SQUIDs experiments.

Besides, is the mathematics describing the two systems even equivalent?

Zz.
 
  • #101


ZapperZ said:
These two statements that I highlighted appear to be contradictory to each other.

The reason why the scenario is conceptually difficult is that it makes OTHER issues difficult. A pendulum has its bob a specific location as a specific time, not spread out all over its trajectory, the latter of which is the conventional picture adopted by standard QM. And there ARE consequences of such a scenario, ranging from molecular bonds, to the existence of the coherent gap in SQUIDs experiments.

Besides, is the mathematics describing the two systems even equivalent?

Zz.

I meant that the probability distribution is constant IN TIME yet the thing is moving. The probability distribution is clearly not constant with regard to position. And no the mathematics describing these two systems are not equivalent. I think that's because of how we perceive things though, perhaps they are equivalent with regard to some other dimension... anyway this is not the point. I was only showing how it's not conceptually difficult even in the classical sense to think that a probability distribution is constant yet have the particle moving.
 
  • #102


I've read all the threads relating to this question but my mind is just having trouble with the concept. Let's take the simplest case: a hydrogen atom with one proton and one electron. They have opposite charges and attract. If I think of each as a particle, then my mind wonders why wouldn't the two particles attract each other and come together and collide.

The only way I can make sense of it is as follows, and tell me if this is an okay way to think of it: the electron is not a particle, but rather a spherical cloud of charge. In this case, I think of it the electron not as a single point but rather as the atmosphere around a planet and the planet itself as the proton (I know the sizes are not to scale). This is the only way I can think of it that makes any sense to me and answers the question of why an electron is not pulled into the nucleus (the proton).
 
  • #103


Re: why doesn't the electron fall into the nucleus!?


This is what happens when we insist on using classical physics to describe a quantum system! Classically, an electron-proton system has no equilibrium state – the electron will spiral into the nucleus while radiating away its orbital energy. There is no such thing as a “classical atom”. There are only “quantum atoms”. And, quantum mechanics is about probabilities. It does not describe the motion of the particles involved. In fact, the electron and the proton are entangled in a way that has no classical analog. We must think of the atom as a single entity. The electron and proton are not separate objects that have independent identities . I know this is not what most of you want to hear, but there is no “electron moving around a nucleus”!

So, what does quantum mechanics tell us about the hydrogen atom? It tells us the possible values to expect IF WE MEASURE the energy, for example, and it tells us the probability of obtaining each energy value. Notice that we do not know the atom’s energy, but only the value we might get as a result of an energy measurement. This is because the atom is further entangled with the energy measuring device: the atom is non-separable from the rest of the experimental apparatus. The bottom line is this – we only know that we have an experimental apparatus involving hydrogen atoms that measures the energy.

It is very difficult to discuss such things because we are using the language of classical physics to describe non-classical events. This is an unavoidable dilemma that physicists are forced to live with. And it certainly generates a lot of controversy!
Best wishes
 
  • #104


JayAaroBe said:
The only way I can make sense of it is as follows, and tell me if this is an okay way to think of it: the electron is not a particle, but rather a spherical cloud of charge. In this case, I think of it the electron not as a single point but rather as the atmosphere around a planet and the planet itself as the proton (I know the sizes are not to scale). This is the only way I can think of it that makes any sense to me and answers the question of why an electron is not pulled into the nucleus (the proton).

This is indeed the most sensible classical view of an atom among the various possibilities, but
it doesn't explain what you'd like it to explain. Indeed, a classical charged electron cloud would still be sucked in by the proton. So, no matter how you do it, classical pictures for quantum phenomena are somewhat limited. The stability of an atom cannot be explained classically, but requires an understanding in terms of quantum mechanics.
 
  • #105


energy and momentum is conserved by the electron...In some sense the electron is in a non-inertial reference frame because of its constant motion or velocity.
 

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