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Why doesn't the normal Zeeman effect produce a band?
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[QUOTE="drvrm, post: 5446968, member: 527528"] in normal zeeman effect the orbital angular momentum states for a particular n (principal quantum number) -which has possibility of description in states of L=0,1,2,...(n-1) which are not split normally ,the external magnetic fields lifts the degeneracy in a manner that only those m(L) values are are available /allowed with m(L) taking -L, (L-1) ...0 ,1,2 ... +L in steps of 1 only. these are the allowed states quantum mechanically [U]therefore the expectation that all cos(theta) values are possible is not allowed. [/U] For example for L=1 a [B]p[/B] state only m(L) are -1, 0, +1 making definite theta with the z axis (magnetic field axis) in a vector model. thereby Considering the [URL='http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/qangm.html#c1']quantization of angular momentum [/URL], this gives equally spaced energy levels displaced from the [U]zero field level [/U]by [ATTACH=full]187069[/ATTACH][ATTACH=full]187070[/ATTACH] so the spectrum can not be continuous and will be spaced by the above. see; [URL]http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/zeeman.html[/URL] for an introductory treatment [/QUOTE]
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Why doesn't the normal Zeeman effect produce a band?
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