Why Don't We Convert Wavelength When Light Enters Glass?

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lha08
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Homework Statement


When 2 glass plates form an air wedge with a fine wire at one end, why don't we convert the given wavelength in air of light into the wavelength in glass since we have to convert it when it is entering in water??
Thanks


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The Attempt at a Solution

 

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mgb_phys said:
Because the fringes are formed in the air gap - the experiment works just as well with two metal mirrors.

so there are gaps in the glass that light passes through so we don't need to convert it?
 
The experiment is to measure fringes formed in the air between the two slides.
The only reason you use glass slides is to be able to see what's happening - all the interference takes place in the air (the wedge gap) between them.
 
mgb_phys said:
The experiment is to measure fringes formed in the air between the two slides.
The only reason you use glass slides is to be able to see what's happening - all the interference takes place in the air (the wedge gap) between them.

If water was surrounding the wedge, would we still keep using the wavelength in air for a problem like that?
 
The path difference between the light reflected at either side of the
air wedge is twice the rhickness of the air wedge.

Since only one of the interfering waves passes through the air, I would
say the interference (superposition) occurs anywhere but he air wedge!
 
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