Why efficiency of induction motor is low for low HP?

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Discussion Overview

The discussion centers on the efficiency of induction motors, particularly focusing on why lower horsepower (HP) motors exhibit decreased efficiency compared to higher HP motors. Participants explore various factors contributing to this phenomenon, including mechanical and electrical losses, motor dimensions, and slip characteristics.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions why the efficiency of a 1/4 HP motor is lower than that of a 1 HP motor, which is stated to be around 85%.
  • Another participant notes that efficiency and power factor generally decrease with lower rated power and velocity, suggesting that increased slip and weight per power unit contribute to this decrease.
  • A proposed explanation includes the relationship between motor dimensions and rated torque, indicating that as power increases, the dimensions and weight per horsepower decrease, leading to lower mechanical and magnetic losses in higher HP motors.
  • A correction is made regarding electrical losses, indicating that these losses are proportional to slip, and that lower slip in higher HP motors results in reduced electrical losses per horsepower.

Areas of Agreement / Disagreement

Participants express varying viewpoints on the factors affecting motor efficiency, with no consensus reached on a singular explanation for the observed decrease in efficiency at lower horsepower ratings.

Contextual Notes

Participants reference specific relationships and equations related to motor dimensions and losses, but the discussion does not resolve the underlying assumptions or dependencies on definitions related to these factors.

srinaath
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why there is a decrease in efficiency of induction motor when power rating is low? example 1 HP motor efficiency is say 85% then 1/4HP motor efficiency is less than 85%? please clear me this doubt?
 
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This might help :smile:
 
Indeed, according to most of catalogues the efficiency and power factor decreases if the rated power decreases [and also if the rated velocity decrease].The slip increases. The weight per power unit increases.
In my opinion this could be the explanation:
The motor dimensions-the stator inside diameter at the air gap- is stated according to motor
rated torque.
D=K*T^(1/3)
For the same rated rpm the torque increases proportionally with the rated power.
T=K*P/rpm then:
Dint=K*P^(1/3)
Actually Weight1/Weight2~=(P1/P2)^(a/3) a=1 to 2.5
That means the weight/hp is less for high hp and then mechanical losses[friction, ventilation] and
magnetic losses are less for more power rated. Also the slip decreases if power increases, so the electrical losses Plosses=Pm*(1-s) will decrease.
 
Correction:
electrical losses=~k*Pmec*s.Then electrical losses/HP=~s.Less slip less electrical losses per HP.
 

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