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Why is 2/(x lnx^2) = 1 / (x ln x) ?

  1. Mar 5, 2010 #1
    1. The problem statement, all variables and given/known data
    2/(x lnx^2) = 1 / (x ln x)
    That is the answer in the back of my textbook. I have reached 2 ( x ln x^2) , but I do not know why it is = to 1 / ( x ln x )

    2. Relevant equations

    3. The attempt at a solution
    I tried to look into precal book to see if I could find information on this "ln simplify process" but I can't find it. I didn't have proper math classes so I am missing a lot of math stuff that people who take calculus should know :/ Please advice. Thank you.
  2. jcsd
  3. Mar 5, 2010 #2


    Staff: Mentor

    Can you simplify ln(x2)? Look in your book for properties of logarithms. They should be close to the beginning of the section that introduces logs.

    Also, this section of the forum is for Calculus & Beyond. Yours is a precalculus question.
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