# Why is 2/(x lnx^2) = 1 / (x ln x) ?

• Knight226
In summary, the student is struggling with simplifying the equation 2/(x lnx^2) = 1 / (x ln x) and is unsure of how to proceed. They have looked for information on the "ln simplify process" in their precalculus book but have not found it. They are seeking advice and clarification on the properties of logarithms to help them solve the problem.

## Homework Statement

2/(x lnx^2) = 1 / (x ln x)
That is the answer in the back of my textbook. I have reached 2 ( x ln x^2) , but I do not know why it is = to 1 / ( x ln x )

## The Attempt at a Solution

I tried to look into precal book to see if I could find information on this "ln simplify process" but I can't find it. I didn't have proper math classes so I am missing a lot of math stuff that people who take calculus should know :/ Please advice. Thank you.

Knight226 said:

## Homework Statement

2/(x lnx^2) = 1 / (x ln x)
That is the answer in the back of my textbook. I have reached 2 ( x ln x^2) , but I do not know why it is = to 1 / ( x ln x )

## The Attempt at a Solution

I tried to look into precal book to see if I could find information on this "ln simplify process" but I can't find it. I didn't have proper math classes so I am missing a lot of math stuff that people who take calculus should know :/ Please advice. Thank you.

Can you simplify ln(x2)? Look in your book for properties of logarithms. They should be close to the beginning of the section that introduces logs.

Also, this section of the forum is for Calculus & Beyond. Yours is a precalculus question.