Why is b^2 = 4 for this ellipse?

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Homework Help Overview

The discussion revolves around the Cartesian equation of an ellipse that must pass through the point (6,0) and has its center at (2,0). Participants are examining why the solution specifies that b^2 equals 4, questioning the assumptions and constraints of the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are exploring the implications of different values for b and how they affect the ellipse's dimensions. There is a focus on defining what "smaller" means in this context and whether the ellipse must fully enclose a circle.

Discussion Status

The discussion is active, with participants questioning the completeness of the problem statement and suggesting that additional conditions may be necessary to determine the smallest ellipse. There is no explicit consensus, but various interpretations are being explored.

Contextual Notes

Some participants note that the problem may lack necessary assumptions, such as the requirement for the ellipse to fully enclose a circle, which could affect the determination of b.

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Homework Statement
Find the Cartesian equation of the smallest ellipse that passes through the point (6,0) and has a centre at (2,0).
Relevant Equations
x^2/a^2 + y^2/b^2 = 1
Hi everyone

The solution for this question has b^2 as 4, but I don't see why it has to be 4. I've tried using different values of b for the ellipse on Desmos, and it is possible to make ellipses with smaller values of b that pass through (6,0).

Have I missed something in the question? Or has the question omitted an assumption (e.g. that the ellipse has to have the same height as the circle)?Thanks

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Darkmisc said:
Homework Statement:: Find the Cartesian equation of the smallest ellipse that passes through the point (6,0) and has a centre at (2,0).
Relevant Equations:: x^2/a^2 + y^2/b^2 = 1

Hi everyone

The solution for this question has b^2 as 4, but I don't see why it has to be 4. I've tried using different values of b for the ellipse on Desmos, and it is possible to make ellipses with smaller values of b that pass through (6,0).
Define 'smaller' in this context!
Darkmisc said:
Have I missed something in the question? Or has the question omitted an assumption (e.g. that the ellipse has to have the same height as the circle)?Thanks
Maybe you should describe in words what the smallest ellipse will be! Where on the ellipse must ##(6,0)## lie?
Darkmisc said:
 
Darkmisc said:
The solution for this question has b^2 as 4, but I don't see why it has to be 4. I've tried using different values of b for the ellipse on Desmos, and it is possible to make ellipses with smaller values of b that pass through (6,0).

View attachment 302317
You are correct There seems to be a problem with the question (Post #1 attachment).

I guess the question should also require that the ellipse fully encloses the circle, or something equivalent to this.

(Also, when answering questions like this, I would include a diagram showing axes, circle and ellipse.)

Edit - typo's.
 
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fresh_42 said:
Define 'smaller' in this context!

Maybe you should describe in words what the smallest ellipse will be! Where on the ellipse must ##(6,0)## lie?
The width of the ellipse would be constrained by having to pass through (6,0), so smaller to me would refer to its height. I'm not sure there's a limit to how flat the ellipse could be. I think b could be made arbitrarily small and the ellipse would still pass through (6,0), so long as a^2 = 16.
 
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Darkmisc said:
The width of the ellipse would be constrained by having to pass through (6,0), so smaller to me would refer to its height. I'm not sure there's a limit to how flat the ellipse could be. I think b could be made arbitrarily small and the ellipse would still pass through (6,0), so long as a^2 = 16.
Yes, I imagined a flat line from ##(6,0)## to ##(-2,0),## too. So either @Steve4Physics is right and it was a typo, or some additional information is missing. I won't care very much.
 
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Darkmisc said:
The width of the ellipse would be constrained by having to pass through (6,0), so smaller to me would refer to its height. I'm not sure there's a limit to how flat the ellipse could be. I think b could be made arbitrarily small and the ellipse would still pass through (6,0), so long as a^2 = 16.
I think you're right, the centre and xmax are defined, but you need another condition else the min height and area are 0.
 
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fresh_42 said:
So either @Steve4Physics is right and it was a typo, or some additional information is missing.
For accuracy, can I note that (in Post #3) I didn't suggest there was a typo' in the question. I suggested additional information was missing.
 
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