What Is the Solution Space for Ax=b in Linear Algebra?

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The discussion centers on the solution space for the equation Ax=b in linear algebra, specifically addressing the fundamental subspaces associated with matrix A: the null space, column space, and row space. The participants clarify that while the null space is a subspace when b=0, the solution set for non-zero b is termed a "linear manifold," which does not contain the origin. The rank-nullity theorem and the dimension theorem for vector spaces are also referenced as essential concepts for understanding these relationships.

PREREQUISITES
  • Understanding of fundamental subspaces in linear algebra: null space, column space, and row space
  • Familiarity with the rank-nullity theorem
  • Knowledge of linear manifolds and their properties
  • Basic concepts of vector spaces and linear combinations
NEXT STEPS
  • Study the rank-nullity theorem in detail to understand its implications on solution spaces
  • Explore the dimension theorem for vector spaces to grasp the relationship between dimensions of subspaces
  • Learn about linear manifolds and their characteristics in R^n
  • Investigate the properties of linear combinations and basis vectors in vector spaces
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Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to clarify concepts related to solution spaces and subspaces.

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When studying linear algebra when encountering a system Ax=b, I always read of the fundamental subspaces of A: N (the null space, all solutions x of Ax=0), the column or domain space of A: (the space spanned by the columns of A, or in other words, all possible b for Ax=b), the row space (the space spanned by the rows of A. I have a harder time wrapping my head around this one).


But I had another question. What about all the possible vectors x for a given b, such that Ax=b ? I get that this wouldn't always work because say, some systems are inconsistent and have no solutions so it would be empty in this case. It seems like this wouldn't necessarily be a subspace because it wouldn't necessarily be closed under addition (just because x is a solution to Ax=b doesn't mean A(2x)=b is a solution). But sometimes it would be a subspace. Because for example, the nullspace would just be the special case where b = 0, the 0 vector, and we know the nullspace is a subspace. Is this "solution space" given special importance? If so what's it called? (I keep calling it a solution space and I just don't know what the proper name of it is)
 
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dumbQuestion said:
When studying linear algebra when encountering a system Ax=b, I always read of the fundamental subspaces of A: N (the null space, all solutions x of Ax=0), the column or domain space of A: (the space spanned by the columns of A, or in other words, all possible b for Ax=b), the row space (the space spanned by the rows of A. I have a harder time wrapping my head around this one).


But I had another question. What about all the possible vectors x for a given b, such that Ax=b ?
If Ax= b, then A(x+ v)= Ax+ Av= b for any v in the null space of A.

I get that this wouldn't always work because say, some systems are inconsistent and have no solutions so it would be empty in this case. It seems like this wouldn't necessarily be a subspace because it wouldn't necessarily be closed under addition (just because x is a solution to Ax=b doesn't mean A(2x)=b is a solution). But sometimes it would be a subspace. Because for example, the nullspace would just be the special case where b = 0, the 0 vector, and we know the nullspace is a subspace. Is this "solution space" given special importance? If so what's it called? (I keep calling it a solution space and I just don't know what the proper name of it is)
The only time a "solution space" (which is, in fact, a standard name for it) is a subspace is when b= 0. In the case that b\ne 0, the "solution set" is a "linear manifold"- something like a line or plane in R3 that does NOTcontain the origin. It can be shown that if v is a vector satisfying Ax= b, then any solution of Ax= b can be written as v plus a vector satisfying Ax= 0. Since Ax= 0 is a subspace, it contains a basis so any solution to Ax= 0 can be written as a linear combination of basis vectors. And so any solution of Ax= b can be written as such linear combination of basis vectors plus v.
 

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