Why is ##dQ = dH## still valid for chemical reaction (Callen)?

[Chestermiller]

Just to give some other examples: You could run a reaction far from equilibrium quasistatically if it requires some homogeneous catalyst and you are using very small concentrations of it. In case of enzymatic reactions, reactions will run very slowly at lower temperatures.

You could also run a reaction reversibly using a van't Hoff equilibrium box.

 

[DrDu]

You could also run a reaction reversibly using a van't Hoff equilibrium box.

Yes, but I understood that the question was whether you can run a non-equilibrium reaction quasistatically, not reversibly.