Why is \( e^{C} = Ce \) but \( e^{x^2+C} = De^{x^2} \)?

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vanceEE
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Why does $$ e^{C} = Ce ?$$
 
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vanceEE said:
Why does $$ e^{C} = Ce ?$$

It doesn't..

If C is an arbitrary constant, it is true that I can say:

$$ e^{C} = e * e^{C-1} = C_{2}e $$

Because $$ e^{C-1} $$ is just some other constant. But it is not the same as C, it is a new constant.
 
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1MileCrash said:
It doesn't..
But $$e^{x^2+C} = De^{x^2} $$ are we just considering e^C to be an arbitrary constant since it is a number multiplied by a number?
 
Last edited:
1MileCrash said:
It doesn't..

If C is an arbitrary constant, it is true that I can say:

$$ e^{C} = e * e^{C-1} = C_{2}e $$

Because $$ e^{C-1} $$ is just some other constant. But it is not the same as C, it is a new constant.
Ok thanks
 
vanceEE said:
But $$e^{x^2+C} = De^{x^2} $$ are we just considering e^C to be an arbitrary constant since it is a number multiplied by a number?
Probably already answered, but here are the details.
ex2 + C = ex2 * eC = D ex2, where D = eC.

Your question is really about the properties of exponents, and not specifically about the natural number e. The basic property here is am + n = am * an.