Why Is Light Not Refracted at the Planar Edge of a Planoconvex Lens?

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Homework Help Overview

The discussion revolves around the behavior of light as it interacts with a planoconvex lens, specifically focusing on why light is not refracted at the planar edge of the lens. Participants explore the principles of refraction and the conditions under which it occurs, referencing diagrams and external resources.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants examine the conditions for refraction at the planar edge versus the curved edge of the lens, questioning the accuracy of a referenced diagram and the implications of light striking surfaces at different angles.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants offer insights into the nature of light's behavior at different interfaces, while others express confusion regarding the diagram's representation of refraction. Clarifications about the conditions under which light is refracted are being discussed.

Contextual Notes

There is mention of a specific diagram and external website that may have contributed to misunderstandings about the refraction of light at the planar edge. Participants are also considering the implications of light traveling at different angles and the effects of the lens's curvature on refraction.

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[SOLVED] Basic optics (GCSEs in 3 days, please help)

Homework Statement


Here is a diagram of light passing through the curved edge of a planoconvex lens.
plano.jpg


When a light ray strikes the planar edge, it is not refracted. Why?

2. The attempt at a solution
The website the diagram came from: http://www-optics.unine.ch/education/optics_tutorials/plano_convex_lens_aberration.html

Light is refracted when it strikes the curved edge of the lens. I know that when light it is not refracted if it passes at 90 degrees to the border between the media. In the diagram, this isn't the case.

I've studied refraction with semicircular glass plates, but light is refracted when it passes out of the straight edge.

Any hints would be really useful.
 
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It's to do with light traveling slower when it enters a denser medium.
If it strikes the curved edge then one end of the light ray will travel slower through the glass while the other is traveling at the original velocity through the air. This causes the light to turn towards the normal of the curve.
If the light ray hits the planar edge, it still enters into a denser medium and will have a lower velocity, but it will travel in a straight line. Imagine a car being the light ray and the glass being sand. When the car drives into the sand at an angle, one wheel will get onto it first, because the sand has more friction, the wheel will travel slower than the other wheel still on the road. This creates a turning effect. If you imagine a car driving into the sand at 90 degress it will not change direction.
Hope this helped.
 
slakedlime, as you have correctly pointed out, the light is refracted by the planar interface. I'm not really sure what they are trying to say... perhaps someone else has seen this before and can enlighten us.
Unless they mean reversing the lens so that the normally incident rays arrive at the planar surface first?
 
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mda said:
Unless they mean reversing the lens so that the normally incident rays arrive at the planar surface first?

I know that incident rays arriving first at the planar surface aren't refracted because they strike the glass at 90 degrees (along the normal). I found that diagram as an applet on this site (which is about chromatic aberrations):

http://www-optics.unine.ch/education/optics_tutorials/plano_convex_lens_aberration.html

I pasted one of the diagrams here. It seems that light isn't bent after coming out of the planar surface. Maybe I'm mistaken? :redface:
 
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In the diagram you give (first post) it is refracted, you just cannot see it clearly, because it's not by a lot.
 
Maybe if you ignore whatever is happening first on the right (assuming the light is going right->left), and imagine the light is just a 'horizontal' beam, like the one in the centre.

Are they not just asking you to talk about the 'normal', as you did above?
 
timothy123 said:
Maybe if you ignore whatever is happening first on the right (assuming the light is going right->left), and imagine the light is just a 'horizontal' beam, like the one in the centre.

Would it be logical to assume that all the light rays are horizontal?

bsimmo said:
In the diagram you give (first post) it is refracted, you just cannot see it clearly, because it's not by a lot.
That's what I first thought, but the website said otherwise. It said that light striking the planar surface wasn't refracted. Maybe the writer was simplifying because the difference is so little?
 
slakedlime said:
When a light ray strikes the planar edge, it is not refracted. Why?
I'd say it was just a sloppy diagram. Light is refracted at both surfaces.
 
I'm a beginning secondary science teacher (admittedly with a biology specialism), and if I had to second guess a GCSE paper, I'd say it was simply asking why there is no refraction at A, whilst there is at B, in the diagram below:

http://img151.imageshack.us/img151/3686/flowroot5110jd8.png

Which you can do, no problem I think! I'm sure you're on track for a good mark.

Obviously, it's hard to say without seeing the paper.. :-)
 
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  • #10
slakedlime said:
That's what I first thought, but the website said otherwise. It said that light striking the planar surface wasn't refracted. Maybe the writer was simplifying because the difference is so little?
I think you are misreading what the website said. The only mention I saw was this:
"As you can see in the previous applet, if the light falls upon the planar interface, it is not bent, and the whole effect will be done by the curved interface. On the other way, the whole lens effect is shared between the two interfaces. Their "effort" is smaller for each interface, so the aberrations are smaller."​
In the first sentence, they are talking about parallel rays striking the plane surface first; since the rays are perpendicular to the plane surface, there is no refraction. But the second sentence correctly states that when parallel rays strike the curved surface first, refraction occurs at both interfaces.
 
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  • #11
Oh, thank-you for pointing that out! :redface: I understand it now. Thanks for your help and time everyone!
 

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