Why Is Momentum Conserved in a Variable Mass System Like a Sand-Laden Cart?

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SUMMARY

The discussion centers on the conservation of momentum in a variable mass system, specifically a sand-laden cart. The equation of motion derived is dV/dt=αv(t)/(m0-αt), where α represents the mass of sand expelled per second and m0 is the initial mass of the cart. It is established that no external forces act on the cart as the sand falls vertically while the cart moves horizontally, thus preserving the cart's momentum. The internal forces within the sand-cart system do not affect the overall momentum, leading to the conclusion that the momentum of the cart remains conserved despite the loss of mass.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of momentum and its conservation
  • Knowledge of variable mass systems in physics
  • Basic calculus for understanding differential equations
NEXT STEPS
  • Study the principles of variable mass systems in classical mechanics
  • Explore the implications of internal forces on momentum conservation
  • Learn about the mathematical modeling of motion with changing mass
  • Investigate real-world applications of momentum conservation in engineering
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Physics students, educators, and anyone interested in advanced mechanics, particularly those studying variable mass systems and momentum conservation principles.

Eitan Levy
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Homework Statement


A cart with no motor moves on a plane. At t=0 it has a mass equal to m0 and some velocity. Each second sand with a mass of α comes out of the cart with a velocity of 0 in relation to the plane. What is the equation of motion of the cart?

Answer: dV/dt=αv(t)/(m0-αt)

Homework Equations


F=dP/dt

The Attempt at a Solution


Basically I can't understand why the momentum of cart is conserved. I mean, if sand comes out of it with a velocity that is different than the velocity of the cart there has to be some force involved right?

What I get is dV/dt=2αv(t)/(m0-αt), because the loss of momentum of the sand translates into some force that the cart applies on it (I believe). What am I doing wrong?
 
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Eitan Levy said:
Basically I can't understand why the momentum of cart is conserved. I mean, if sand comes out of it with a velocity that is different than the velocity of the cart there has to be some force involved right?

No force will affect the motion of the cart because the sand particles fall vertically downwards while the cart moves in a horizontal direction. Thus, there is no force which affects the linear momentum of the cart.
 
Adhruth Ganesh said:
No force will affect the motion of the cart because the sand particles fall vertically downwards while the cart moves in a horizontal direction. Thus, there is no force which affects the linear momentum of the cart.
But what causes the sand to suddenly lose its momentum?
 
There is an internal force in the sand-card system. However, since the sand momentum is zero, conservation of momentum in the sand-cart system therefore requires that the momentum of the cart remains the same. Note that the momentum of just the cart is actually increasing because some of that momentum was previously carried by the sand.
 
Eitan Levy said:
But what causes the sand to suddenly lose its momentum?
The problem says that it does. If you wish, you can imagine a gremlin standing on the cart and carefully throwing grains of sand rearward just hard enough so that they become motionless with respect to the ground beneath.
 
Adhruth Ganesh said:
No force will affect the motion of the cart because the sand particles fall vertically downwards
How did the sand go from moving at the same velocity as the cart to falling vertically (in the rest frame)?
 

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